[英]How can I extract url from json data with escaped “\” in java
I need to extract url from json filed. 我需要从json字段中提取网址。 (replace it with "" and do not break the json format), so that there's no url in json.
(将其替换为“”,并且不要破坏json格式),以便json中没有url。
the url looks in this way 网址看起来是这样的
"source":"\u003ca href=\"http:\/\/twitter.com\/download\/iphone\",
"profile_image_url_https":"https:\/\/pbs.twimg.com\/profile_images\/3475536942\/2b0ccd9e42754adf7e22947037dd8c34_normal.jpeg","profile_banner_url":"https:\/\/pbs.twimg.com\/profile_banners\/488849893\/1364691799",
Simply use a lightweight JSON parser such as this reference implementation in Java 只需使用轻量级的JSON解析器(例如Java中的此参考实现)
To overwrite, say, the source
property to "blah", it is possible to do things as simple as 要将
source
属性覆盖为“ blah”,可以执行以下操作:
String newJsonString = new JSONObject(originalJsonString).putString("source","blah").toString();
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