[英]How to take date frequent change (day by day)
I want to change date in every day in my result. 我想每天更改结果中的日期。 How it is possible
怎么可能
like example: WHERE REPLY_dATE
BETWEEN '2017-03-17 12:00:00 AM' AND '2017-03-17 4:00:00 PM I want to replace=====2017-01-01 12:00:00 AM====today_Date 2017-03-17 4:00:00 PM=======current date 像这样的例子:'2017-03-17 12:00:00 AM'和'2017-03-17 4:00:00 PM之间的WHERE
REPLY_dATE
我要替换===== 2017-01-01 12:00: 00 AM ==== today_Date 2017-03-17 4:00:00 PM =======当前日期
Use LEAST()
for the first step: 第一步使用
LEAST()
:
LEAST(264, Round(SUM(TIMESTAMPDIFF(MINUTE,Request_Date, REPLY_dATE))/480)) as WH
Use CASE
for second step: 使用
CASE
进行第二步:
CASE WHEN ROUND((126720-sum(TIMESTAMPDIFF(MINUTE,Request_Date, REPLY_dATE)))/480) < 0 THEN 0
ELSE LEAST(264, Round(SUM(TIMESTAMPDIFF(MINUTE,Request_Date, REPLY_dATE))/480))
END
If you need WH
and VH
as well, you can use a sub-query to avoid redundancy: 如果还需要
WH
和VH
,则可以使用子查询来避免冗余:
SELECT VH, WH,
CASE
WHEN (SELECT VH) < 0 THEN 0
ELSE (SELECT WH)
END AS MyComputedColumn
FROM
(
SELECT
ROUND((126720-sum(TIMESTAMPDIFF(MINUTE,Request_Date, REPLY_dATE)))/480) as VH,
LEAST(264, Round(SUM(TIMESTAMPDIFF(MINUTE,Request_Date, REPLY_dATE))/480)) as WH
FROM bbt2.new_table
) AS X;
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