Mysqli查询不返回任何信息？

Question

Im attempting to find the next date. For what ever reason, the below code is not returning any information. I have 1 entry formatted as such : 2017-03-18 12:37:00.... what am I doing wrong?

<?php
define('DB_SERVER', 'localhost');
define('DB_USERNAME', 'user');
define('DB_PASSWORD', 'pass');
define('DB_DATABASE', 'db');
$link = mysqli_connect(DB_SERVER,DB_USERNAME,DB_PASSWORD,DB_DATABASE);
$query = "SELECT * FROM group WHERE date_time >= NOW() order by date_time LIMIT 1";
$next = mysqli_query($link, $query);
echo $next;
?>

Answer 1

You need to call a fetch function to get the data from the query. You should also check if it found anything; the fetch function will return null instead of an array if no rows were matched by the query.

$query = "SELECT * FROM `group` WHERE date_time >= NOW() ORDER BY date_time LIMIT 1";
$result = mysqli_query($link, $query);
$row = mysqli_fetch_assoc($result);
if ($row) {
    $date_time = $row['date_time'];
    echo "Next date is " . $date_time;
} else {
    echo "No time after now in the table.";
}

Answer 2

With your code you return your query pointer. You're missing one line to fetch the entries.

https://secure.php.net/manual/de/mysqli-result.fetch-assoc.php

Here is a good example how to achieve that.

if ($result = $mysqli->query($query)) {

    /* fetch associative array */
    while ($row = $result->fetch_assoc()) {
        printf ("%s (%s)\n", $row["Name"], $row["CountryCode"]);
    }

    /* free result set */
    $result->free();
}