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Golang MongoDB聚合

[英]Golang mongodb aggregation

I have a collection of users. 我有一组用户。 User have an int64 "id", and lets say "avatar", "name" and an array of other users ids. 用户有一个int64“ id”,并说“ avatar”,“ name”和其他用户ID的数组。 What I want to achieve is to query SINGLE user, but instead of getting an array with his friends ids I want to get an array of his friends, containing their names and avatars. 我想要实现的是查询SINGLE用户,但是与其获取一个带有其朋友ID的数组,不如获取一个包含其姓名和头像的朋友的数组。 How to achieve it in golang? 如何在golang中实现它? I have found some kind of what I need - "lookup" function, but I cannot understand how to use it right. 我已经找到了所需的某种东西-“查找”功能,但是我不明白如何正确使用它。

You cannot apply $lookup to array directly, but you can to $unwind it first. 您不能直接将$ lookup应用于数组,但可以先对其进行$ unwind

Without example documents, the code snippet below is rather a general approach: 如果没有示例文档,则下面的代码段是一种通用方法:

pipeline := []bson.M{ 
    bson.M{"$match": bson.M{"_id": userId }},
    bson.M{"$unwind": "$otherUsersIdsArrayName"},
    bson.M{
        "$lookup": bson.M{ 
            "from": userCollectionName, 
            "localField": otherUsersIdsArrayName, 
            "foreignField": "id", 
            "as": "friend"
        }
    },
    bson.M{"$unwind": "$friend"},
    bson.M{
        "$group": bson.M{
            "_id": "id",
            "id": bson.M{"$first": "$id"},
            "name": bson.M{"$first": "$name"},
            "avatar": bson.M{"$first": "$avatar"},
            otherUsersIdsArrayName: bson.M{ "$push": "$friend"}
        }
    }
}
pipe := collection.Pipe(pipeline)
resp := []bson.M{}
err = pipe.All(&resp)

I should mention that aggregation/pipe returns bson.M , not hydrated User objects. 我应该提到聚合/管道返回bson.M ,而不是水合的User对象。 Mongo is not a relational database after all. 毕竟,Mongo不是关系数据库。

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