Swift：如何防止同时擦拭两个表格单元格？

Question

I have a table view with cells that the user can swipe to delete the row. I'm receiving a fatal error: Index out of range error whenever I swipe two rows at once (with two fingers, one on each row).

I've added these 4 lines in my OrdersViewController :

  override func viewDidLoad() {
    ...
    self.view.isMultipleTouchEnabled = false
    self.view.isExclusiveTouch = true
    self.ordersTable.isMultipleTouchEnabled = false
    self.ordersTable.isExclusiveTouch = true
  }

in an effort to try to change this behavior so that only one cell is swiped at a time, but nothing has changed. I can still use two fingers on two different rows to swipe back and forth at the same time.

Is there another way?

None of the IsExclusiveTouch and IsMultipleTouchEnabled is working regardless of where I put it. I wonder if it has anything to do with me using this library github.com/alikaragoz/MCSwipeTableViewCell

It could also be because I'm using Firebase?

Answer 1

First of all set delegates of gesture and then use this delegate, it could help you :

override func gestureRecognizer(_ gestureRecognizer: UIGestureRecognizer, shouldRecognizeSimultaneouslyWith otherGestureRecognizer: UIGestureRecognizer) -> Bool {
    return false;
}

Answer 2

I eventually did this, using the callbacks made available by the table cell pod i'm using:

class OrderTableManager {
  static var swiping = false
}

class OrderPreparingTableViewCell: MCSwipeTableViewCell, MCSwipeTableViewCellDelegate {
  override func gestureRecognizerShouldBegin(_ gestureRecognizer: UIGestureRecognizer) -> Bool {
    if !OrderTableManager.swiping {
      OrderTableManager.swiping = true
      return true
    } else {
      return false
    }
  }

  // MARK: Public
  func swipeTableViewCellDidEndSwiping(_ cell: MCSwipeTableViewCell!) {
    OrderTableManager.swiping = false
  }

  func displayOrder(order: AppState.Order, clock: Clock, fDone: @escaping SwipeHandler, fDelete: @escaping SwipeHandler) -> OrderPreparingTableViewCell {
    ...

    self.delegate = self

    ...
  }