返回后无法重新加载ionic应用程序脚本

Question

In my ionic app when script included in index.html is loaded for the first time but after coming back to same screen script is not running. 在我的离子应用程序中，首次加载index.html包含的脚本时，但回到同一屏幕后，脚本未运行。

<!DOCTYPE html>
<html>
    <head>
        <meta charset="utf-8">
        <meta name="viewport" content="initial-scale=1, maximum-scale=1, user-scalable=no, width=device-width">
        <title></title>
        <link href="lib/ionic/css/ionic.css" rel="stylesheet">
        <link href="css/style.css" rel="stylesheet">
        <script src="lib/ionic/js/ionic.bundle.js"></script>
        <script src="cordova.js"></script>
        <script src="js/app.js"></script>
        <script src="js/controllers.js"></script>
        <script>alert(1)</script>
    </head>
    <body ng-app="starter"> 
<ion-nav-view> </ion-nav-view>
    </body>
</html>

homepage.html homepage.html

  <ion-view>
 <ion-nav-bar align-title="center" class=" bar-royal">
     <ion-nav-title>
  <span>Find Hotels</span>
 </ion-nav-title>
  </ion-nav-bar >
<ion-content  padding="true">
alerted 1 on initial load but not after moving back to same page
 </ion-content>
</ion-view>

Answer 1

Keep in mind that Ionic chaches the views, so controllers are called only on app start or when you disable the caching. 请记住，Ionic会阻塞视图，因此仅在应用程序启动或禁用缓存时才调用控制器。

You can listen to the $ionicView.enter event and insert in the callback function the code that you need to execute every time the view is active. 您可以侦听$ ionicView.enter事件，并在回调函数中插入每次视图处于活动状态时需要执行的代码。

  $scope.$on('$ionicView.enter', function (e) {
  //insert here the code to execute every time the page is active
});

返回后无法重新加载ionic应用程序脚本

问题描述

1 个解决方案

解决方案1
0 2017-03-17 12:01:42

返回后无法重新加载ionic应用程序脚本

问题描述

1 个解决方案

解决方案1 0 2017-03-17 12:01:42

解决方案1
0 2017-03-17 12:01:42