[英]Overwrite/append to multiple-value column in R data.frame
I have a data frame which contains a column in which I want to put multiple values (it can have a different amount of values per record). 我有一个数据框,其中包含一列,我想在其中放置多个值(每个记录可以有不同数量的值)。
I'm trying to append data to it using a for loop but it keeps giving the error: 我正在尝试使用for循环将数据追加到它,但是它不断给出错误:
Error in `[<-.data.frame`(`*tmp*`, 1, "piet", value = c(1, 2)) :
replacement has 2 rows, data has 1
Is it impossible to overwrite/append to this column? 是否不可能覆盖/附加到此列? Small example code:
小示例代码:
a = data.frame(piet=numeric())
a[1,'piet'] = c(1)
a[1,'piet'] = c(1,2) # this throws the error
I realise there are better ways than using a for loop, but my data is spread out somewhat randomly over multiple .csv files (of which some have overlapping records, whose results I'm trying to combine here). 我意识到有比使用for循环更好的方法,但是我的数据多少随机分布在多个.csv文件中(其中某些文件具有重叠的记录,在此尝试合并其结果)。
Ok this is really weird but it works using list(c())
(thanks @Frank) and a very specific coding format: 好的,这确实很奇怪,但是它可以使用
list(c())
(感谢@Frank)和非常特定的编码格式来工作:
a = data.frame(piet=list()) #initialize data frame
a[1,'piet'] = '' # create first row
a$piet[c(T)] = list(c(1,2,3)) # overwrite with list
a$piet[c(T)] = list(c(4,5,6)) # overwrite with new list
a$piet[c(T)] = list(c(unlist(a[1,'piet']),8,9)) # append to existing list
final contents of a: 最终内容:
> a
piet
1 4, 5, 6, 8, 9
Note that the a$piet[row selection]
is mandatory as well as using list(c())
! 注意
a$piet[row selection]
是强制性的, a$piet[row selection]
使用list(c())
!
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