[英]Android XML Reader Reads Once
i just tried to make a XML Reader but i had some troubles. 我只是想制作一个XML Reader,但遇到了一些麻烦。 When I parse the XML file it says there is just one tag and read just this one.
当我解析XML文件时,它说只有一个标签,并且只能读取这个标签。 But there is more than one.
但是不止一个。 Here is my code:
这是我的代码:
@Override
protected Void doInBackground(Void... voids) {
try {
URL url = new URL(QuizActivity.fileUrl);
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new InputSource(url.openStream()));
document.getDocumentElement().normalize();
NodeList sorular = document.getElementsByTagName("sorular");
Log.d("Soru Sayısı", String.valueOf(sorular.getLength()));
for(int i = 0; i < sorular.getLength(); i++){
Node sorularNode = sorular.item(i);
Element sorularElement = (Element) sorularNode;
NodeList siraNodeList = document.getElementsByTagName("sira");
Element siraElement = (Element) siraNodeList.item(i);
NodeList textNodeList = document.getElementsByTagName("text");
Element textElement = (Element) textNodeList.item(i);
NodeList aNodeList = document.getElementsByTagName("a");
Element aElement = (Element) aNodeList.item(i);
NodeList bNodeList = document.getElementsByTagName("b");
Element bElement = (Element) bNodeList.item(i);
NodeList cNodeList = document.getElementsByTagName("c");
Element cElement = (Element) cNodeList.item(i);
NodeList dNodeList = document.getElementsByTagName("d");
Element dElement = (Element) dNodeList.item(i);
NodeList eNodeList = document.getElementsByTagName("e");
Element eElement = (Element) eNodeList.item(i);
NodeList dogruNodeList = document.getElementsByTagName("dogru");
Element dogruElement = (Element) dogruNodeList.item(i);
int sira = Integer.parseInt(siraElement.getChildNodes().item(i).getNodeValue());
SinavActivity.soruText.put(sira, textElement.getChildNodes().item(i).getNodeValue());
SinavActivity.cevap_a.put(sira, aElement.getChildNodes().item(i).getNodeValue());
SinavActivity.cevap_b.put(sira, bElement.getChildNodes().item(i).getNodeValue());
SinavActivity.cevap_c.put(sira, cElement.getChildNodes().item(i).getNodeValue());
SinavActivity.cevap_d.put(sira, dElement.getChildNodes().item(i).getNodeValue());
SinavActivity.cevap_e.put(sira, eElement.getChildNodes().item(i).getNodeValue());
SinavActivity.dogruCevap.put(sira, dogruElement.getChildNodes().item(i).getNodeValue().trim());
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
}
return null;
}
XML File: XML档案:
<?xml version="1.0" encoding="utf-8"?>
<sorular>
<Matematik>
<soru>
<sira>1</sira>
<text>Bir sınıftaki öğrencilerin % 40 ı kız öğrencidir. Kız öğrencilerin % 90 ı, erkek öğrencilerin %80 matematik dersinden başarılıdır. Buna göre, bu sınıfın matematik dersinden başarısı yüzde kaçtır?</text>
<a>84</a>
<b>46</b>
<c>20</c>
<d>12</d>
<e>50</e>
<dogru>A</dogru>
</soru>
<soru>
<sira>2</sira>
<text>A ve B boş olmayan 2 kümedir 2.s(A)=3.s(B)= 5.s(A ∩ B) olduğuna göre s(A-B) en az kaçtır?</text>
<a>8</a>
<b>10</b>
<c>2</c>
<d>9</d>
<e>12</e>
<dogru>D</dogru>
</soru>
</Matematik>
If I write NodeList sorular = document.getElementsByTagName("sorular");
如果我写
NodeList sorular = document.getElementsByTagName("sorular");
it says count of NodeList = 1
but if I write NodeList sorular = document.getElementsByTagName("soru");
它说
NodeList = 1
计数NodeList = 1
但是如果我写NodeList sorular = document.getElementsByTagName("soru");
it says the count = 2
but it gives me a NullPointerException 它说
count = 2
但它给了我一个NullPointerException
because siraElement.getChildNodes().getLength()
will always return 1
element so when 因为
siraElement.getChildNodes().getLength()
将始终返回1
元素,所以当
siraElement.getChildNodes().item(i).getNodeValue() //i=0
so the first node will be at 0
index but when i=1
then will be no Node
at index 1
因此第一个节点将在
0
索引,但是当i=1
然后将没有Node
在索引1
siraElement.getChildNodes().item(i).getNodeValue() //i=1 error
so you can fetch the always from 0
index 这样就可以从
0
索引中获取Always
int sira = Integer.parseInt(siraElement.getChildNodes().item(0).getNodeValue());
// ^^
plus do the same for all values like below 加上对所有如下所示的值执行相同操作
textElement.getChildNodes().item(0).getNodeValue()
...
dogruElement.getChildNodes().item(0).getNodeValue().trim()
As Pavneet_Singh said I edited and here is the code: 正如Pavneet_Singh所说,我进行了编辑,这是代码:
@Override
protected Void doInBackground(Void... voids) {
try {
URL url = new URL(QuizActivity.fileUrl);
DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = factory.newDocumentBuilder();
Document document = builder.parse(new InputSource(url.openStream()));
Element rootElement = document.getDocumentElement();
NodeList sorular = rootElement.getElementsByTagName("soru");
for(int i = 0; i < sorular.getLength(); i++){
Node soru = sorular.item(i);
Element soruElement = (Element) soru;
String siraText = soruElement.getElementsByTagName("sira").item(0).getTextContent();
String text = soruElement.getElementsByTagName("text").item(0).getTextContent();
String a = soruElement.getElementsByTagName("a").item(0).getTextContent();
String b = soruElement.getElementsByTagName("b").item(0).getTextContent();
String c = soruElement.getElementsByTagName("c").item(0).getTextContent();
String d = soruElement.getElementsByTagName("d").item(0).getTextContent();
String e = soruElement.getElementsByTagName("e").item(0).getTextContent();
String dogru = soruElement.getElementsByTagName("dogru").item(0).getTextContent();
int sira = Integer.parseInt(siraText);
SinavActivity.soruText.put(sira, text);
SinavActivity.cevap_a.put(sira, a);
SinavActivity.cevap_b.put(sira, b);
SinavActivity.cevap_c.put(sira, c);
SinavActivity.cevap_d.put(sira, d);
SinavActivity.cevap_e.put(sira, e);
SinavActivity.dogruCevap.put(sira, dogru);
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
}
return null;
}
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