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如何编写查询以从正好25分钟回到15分钟之间获取数据? Oracle SQL

[英]How to write a query to fetch data from exactly 25 mins back to 15 mins back? Oracle sql

I have a query like below; 我有一个类似下面的查询;

SELECT fielda,fieldb,fieldc  
from mytable 
where timefield between to_date((to_char(sysdate-1/24, 'DD-MON-YYYY HH24') || ':00:00'), 'DD-MON-YYYY HH24:MI:SS') 
                    and to_date((to_char(sysdate-1/24, 'DD-MON-YYYY HH24') || ':59:59'), 'DD-MON-YYYY HH24:MI:SS');

This query takes value from the 0 th and 59 th minute of hour before previous hour. 该查询从前一小时的第0分钟到第59分钟0 What I want is, I want to run a query, which runs on 10th minute. 我想要的是,我想运行一个查询,该查询在第10分钟运行。 The query should fetch rows from my table, where time is between 25 minures and 15 minutes related to the current. 该查询应从我的表中获取行,其中的时间与当前表之间的时间在25分钟到15分钟之间。 For example, I run the query in 09:10:00 and some seconds. 例如,我在09:10:00和几秒钟内运行查询。 It should fetch rows where timefield is between 08:50 and 08:59:00 (i want to include data in 8:50 and 8:59). 它应该获取时间字段在08:50和08:59:00之间的行(我想在8:50和8:59中包含数据)。 How can I do this? 我怎样才能做到这一点?

You'd truncate SYSDATE to the minute and subtract the desired interval. 您将SYSDATE截断为分钟,然后减去所需的时间间隔。 Use >= and < in order to deal with seconds and fractions thereof properly. 使用>=<为了正确处理秒及其分数。

select fielda, fieldb, fieldc
from mytable 
where timefield >= trunc(sysdate, 'minute') - interval '25' minute
  and timefield <  trunc(sysdate, 'minute') - interval '20' minute;
SELECT *
FROM mytable 
WHERE timefield >= sysdate - (25/1440)
  AND timefield <= sysdate - (10/1440)

24*60 = 1440 24 * 60 = 1440

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