[英]Assigning a value of pointer to a 2D array
I have this following piece of code which is working fine: 我有以下这段代码正常工作:
int array[16][2] = {{0}};
void *buffer_ptr = NULL;
get_buffer(&buffer_ptr); // This is a function which gives me the address of
buffer ptr
file_read(handle, size, buffer_ptr); // This function reads and stores data into buffer_ptr
Now I want to copy this read value into buffer_ptr into array. 现在我想将这个读取值复制到buffer_ptr中。 I am doing this currently which works:
我这样做目前有效:
for (i = 0; i < 16; i++)
{
array[i][0] = *((int *)buffer_ptr+(2*i));
array[i][1] = *((int *)buffer_ptr+(2*i)+1);
}
But I am sure there is a better way to do this. 但我相信有更好的方法可以做到这一点。
Thanks. 谢谢。
But I am sure there is a better way to do this.
但我相信有更好的方法可以做到这一点。
Yes, read directly into the array. 是的,直接读入数组。 There's no need for the intermediate buffer.
不需要中间缓冲区。
I'm going to guess your file is a bunch of 4 byte integers and you want them two at a time. 我猜你的文件是一堆4字节的整数,你希望它们一次两个。 First, use a fixed width type for
array
else you might get the wrong size integer. 首先,对
array
使用固定宽度类型,否则可能会得到错误的大小整数。
#include <stdint.h>
int32_t array[16][2] = {{0}};
Then read straight from the file into the array, two 4 byte integers at time. 然后直接从文件读入数组,两个4字节整数。
FILE *fp = fopen(file, "rb");
if( fp == NULL ) {
fprintf(stderr, "Could not open '%s' for reading: %s\n", file, strerror(errno));
exit(1);
}
for (int i = 0; i < 16; i++)
{
fread(array[i], 4, 2, fp);
}
I believe you can even cut that down to a single read. 我相信你甚至可以把它减少到一次阅读。
fread(array, 4, 32, fp);
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