[英]How to split a string in SPARQL
I'm trying to get the Name of a triple, to separate the PREFIX from the value, and to show these splitted strings in two different columns. 我正在尝试获取三元组的名称,以将PREFIX与值分开,并在两个不同的列中显示这些拆分的字符串。
For example with foaf:Person 例如使用foaf:Person
?prefix | ?name
foaf: | Person
I saw there are some solutions with SUBSTR, but I don't know how to use it in my case. 我看到SUBSTR有一些解决方案,但是我不知道如何在我的情况下使用它。
Any idea ? 任何想法 ?
Thank you by advance :-) 预先感谢您:-)
There are no prefixed URIs in RDF, this is just a concept of presentation but not part of the data. RDF中没有前缀URI,这只是表示的概念,而不是数据的一部分。 What you get by simple SPARQL queries would be a resource with the full URI, ie for your example http://xmlns.com/foaf/0.1/Person
. 通过简单的SPARQL查询得到的将是具有完整URI的资源,即对于您的示例http://xmlns.com/foaf/0.1/Person
。 What you can do by string functions is to split by the namespace and a local name, as you already found out. 您已经发现,通过字符串函数可以执行的操作是按名称空间和本地名称进行拆分。
If you really want to have a prefixed URI, you need a prefix mapping first, eg foaf -> http://xmlns.com/foaf/0.1/
. 如果您确实希望有一个前缀URI,则首先需要一个前缀映射,例如foaf -> http://xmlns.com/foaf/0.1/
。 Then you could do the following: 然后,您可以执行以下操作:
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
SELECT ?prefixedName
(strbefore(?prefixedName,":") as ?prefix)
(strafter(?prefixedName,":") as ?name) {
# dummy value
VALUES ?uri {<http://xmlns.com/foaf/0.1/Person> }
# get a prefixed name of the URI as string literal
BIND(replace(str(?uri), str(foaf:), "foaf:") as ?prefixedName)
}
Output: 输出:
+--------------+--------+--------+
| prefixedName | prefix | name |
+--------------+--------+--------+
| foaf:Person | foaf | Person |
+--------------+--------+--------+
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.