剪接函数未从数组中删除2个连续字符串

Question

function filter_list(l) {
    l.map((item,i,main) => {
     if(typeof item==="string")
     {return main.splice(i,1);}
      else
      return item;
    });
  console.log(l);
}
filter_list([1,'a','b','c',0,15,'k','e']);

here i am expecting output of [1, 0, 15] . But instead it is giving me [1, "b", 0, 15, "e"] . it seems to not removing strings one exists after another. Also i am trying to get the updated array in a new array variable but i don't have any idea how to do that here. Some help would be very much appreciated.

Answer 1

It's much easier to use the filter function and return true for everything that's not a string .

var a = [1, 'a', 'b', 'c', 0, 15, 'k', 'e'];
var b = a.filter(function (item) {
    return ! (typeof item === 'string');
});

Answer 2

Problem is that when you splice element from original array you get problem in iteration of map() , so for example when you remove a with index of 1 now the next element with index of 2 is c because original array is now this [ 1, "b", "c", 0, 15, "k", "e" ] so you skip b . If you don't remove elements you can see that map will match not numbers in your code.

 function filter_list(l) { l.map((item, i, main) => { if (typeof item == "string") main[i] = null }) return l; } console.log(filter_list([1, 'a', 'b', 'c', 0, 15, 'k', 'e']))