[英]Iterate over Worksheets, Rows, Columns
I want to print all data (all rows) of a specific column in python using openpyxl
I am working in this way;我想使用
openpyxl
在 python 中打印特定列的所有数据(所有行)我正在以这种方式工作;
from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active
for i in sheet:
print(sheet.cell(row=i, column=2).value)
But it gives但它给
if row < 1 or column < 1: TypeError: unorderable types: tuple() < int()
如果行 < 1 或列 < 1: TypeError: unorderable types: tuple() < int()
Because i am iterating in row=i
.因为我在
row=i
迭代。 If I use sheet.cell(row=4, column=2).value
it print the value of cell.如果我使用
sheet.cell(row=4, column=2).value
它打印单元格的值。 But how can I iterate over all document?但是如何遍历所有文档?
Edit 1编辑 1
On some research, it is found that data can be get using Sheet Name.在一些研究中,发现可以使用 Sheet Name 获取数据。 The
Sheet 1
exists in the .xlsx
file but its data is not printing. Sheet 1
存在于.xlsx
文件中,但其数据未打印。 Any problem in this code?这段代码有什么问题吗?
workbook = load_workbook('---------------/dataset.xlsx')
print(workbook.get_sheet_names())
worksheet =workbook.get_sheet_by_name('Sheet1')
c=2
for i in worksheet:
d = worksheet.cell(row=c, column=2)
if(d.value is None):
return
else:
print(d.value)
c=c+1
Read the OpenPyXL Documentation阅读OpenPyXL 文档
Iteration over all worksheets
in a workbook
, for instance:迭代
worksheets
workbook
所有worksheets
,例如:
for n, sheet in enumerate(wb.worksheets):
print('Sheet Index:[{}], Title:{}'.format(n, sheet.title))
Output :
输出:
Sheet Index:[0], Title: Sheet Sheet Index:[1], Title: Sheet1 Sheet Index:[2], Title: Sheet2
Iteration over all rows
and columns
in one Worksheet:迭代一个工作表中的所有
rows
和columns
:
worksheet = workbook.get_sheet_by_name('Sheet')
for row_cells in worksheet.iter_rows():
for cell in row_cells:
print('%s: cell.value=%s' % (cell, cell.value) )
Output :输出:
<Cell Sheet.A1>: cell.value=²234
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.C1>: cell.value=C1
<Cell Sheet.D1>: cell.value=D1
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2
Iteration over all columns
of one row
, for instance row==2
:迭代所有
columns
一row
,例如row==2
:
for row_cells in worksheet.iter_rows(min_row=2, max_row=2):
for cell in row_cells:
print('%s: cell.value=%s' % (cell, cell.value) )
Output :输出:
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2
Iteration over all rows
, only column
2 :迭代所有
rows
,仅第2 column
:
for col_cells in worksheet.iter_cols(min_col=2, max_col=2):
for cell in col_cells:
print('%s: cell.value=%s' % (cell, cell.value))
Output :输出:
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.B3>: cell.value=9.8
<Cell Sheet.B4>: cell.value=10.1
<Cell Sheet.B5>: cell.value=7.7
Tested with Python:3.4.2 - openpyxl:2.4.1 - LibreOffice: 4.3.3.2用 Python 测试:3.4.2 - openpyxl:2.4.1 - LibreOffice:4.3.3.2
Try this,尝试这个,
from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active
row_count = sheet.max_row
for i in range(row_count):
print(sheet.cell(row=i, column=2).value)
This code will read a sheet as if it was a csv and populatte a list of dictionaries in result
using the first row as the column titles.此代码将读取工作表,就像它是一个 csv 并使用第一行作为列标题填充
result
中的字典列表。
from openpyxl import load_workbook
result = []
wb = load_workbook(filename=file_name)
sheet = wb.active
col_count = sheet.max_column
column_names = {}
for c in range(1, col_count):
heading = sheet.cell(row=1, column=c).value
if not heading:
col_count = c
break
column_names[c] = heading
for r, row_cells in enumerate(sheet.iter_rows(2), 2):
row = {}
for c in range(1, col_count):
value = sheet.cell(row=r, column=c).value
if type(value) == datetime:
value = value.strftime('%Y-%m-%d')
row[column_names[c]] = value
result.append(row)
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