[英]Add multiple values to one key in dictionary with for loop
I'm using a similar method in a function I'm using. 我正在使用的函数中使用类似的方法。 Why do I get a key error when I try to do this? 尝试执行此操作时为什么会出现关键错误?
def trial():
adict={}
for x in [1,2,3]:
for y in [1,2]:
adict[y] += x
print(adict)
adict
starts off empty. adict
开始是空的。 You can't add an integer to a value that doesn't already exist. 您不能将整数添加到尚不存在的值。
You did not initialize adict
for each key. 您没有为每个键初始化adict
。 You can use defaultdict
to solve this issue: 您可以使用defaultdict
解决此问题:
from collections import defaultdict
def trial():
adict=defaultdict(int)
for x in [1,2,3]:
for y in [1,2]:
adict[y] += x
print(adict)
trial()
The result is defaultdict(<class 'int'>, {1: 6, 2: 6})
结果为defaultdict(<class 'int'>, {1: 6, 2: 6})
There is no value assigned to adict[y]
when you first use it. 首次使用adict[y]
时,没有分配任何值。
def trial():
adict={}
for x in [1,2,3]:
for y in [1,2]:
if y in adict: # Check if we have y in adict or not
adict[y] += x
else: # If not, set it to x
adict[y] = x
print(adict)
Output: 输出:
>>> trial()
{1: 6, 2: 6}
You should modify youre code like this: 您应该像这样修改您的代码:
def trial():
adict={0,0,0}
for x in [1,2,3]:
for y in [1,2]:
adict[y] += x
print(adict)
"adict" has no entries. “ adict”没有任何条目。 So adict[1] fails because it is accessing a variable that does not exist. 因此adict [1]失败,因为它正在访问不存在的变量。
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