Long.toBinaryString没有为827.0返回预期的二进制字符串

Question

I'm working with double s and need to find the binary version of 827.0 .

From looking around the way to do it is this .

So I do:

double myDouble = 827.0;
Long.toBinaryString(Double.doubleToRawLongBits(myDouble))

However this is returning:

100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000100000010001001110110000000000000000000000000000000000000000000

instead of 1100111011 .

Any idea where I'm going wrong?

Answer 1

this should work:

double myDouble = 827.0;
System.out.println(Long.toBinaryString((long) myDouble));