审查在STDIN中找到的单词并打印到STDOUT不起作用

Question

My program is supposed to take any number of one-word text string arguments, each less than 128 characters long. It copies any text from stdin to stdout, except that any of the words seen in the input are replaced with the word CENSORED. So far it kinda works. Any ideas on how I can fix it?

#include <stdlib.h>
#include <stdio.h>
#include <string.h>

int main(int argc, char* argv[]){
char word[128];
int index = 0;
int c = getchar();

while (c != EOF){
    //checks for letter and adds to word[]
    if ((c>='A' && c<='Z') || (c>='a' && c<='z') || c == '\''){
        word[index] = (char)c;
        index++;
        word[index] = '\0';
    }
    //when c is not a letter or ' (end of word)
    else{ 
        if (index > 0){
            int found;
            for (int i=1;i<argc;i++){
                //if word[] is found in input censor it
                if (strcmp(word,argv[i]) == 0){
                    printf("CENSORED");
                    found = 1;
                    break;
                }
            }
            //prints word[] if it's not in input
            if (found != 1){
                printf("%s",word);
            }

        }
        //resets word[] and index / prints value of c
        word[0] = '\0';
        index = 0;
        printf("%c",(char)c);
    }
    //increment c
    c = getchar();
}
}

Answer 1

I see two problems. First, you should not be overflowing your buffer if you do get a word >127 characters. Change:

    word[index] = (char)c;
    index++;

to:

    if ( index+1 < sizeof(word) ) {
        word[index] = (char)c;
        index++;
    }

The other problem, likely the one you have noticed, is that you aren't initializing found . Make it:

        int found = 0;