PHP创建1个数组，其中4个数组按索引排序

Question

I have 4 arrays, each one holds another column of a table, I would like to create one array with the data ordered per array[$i]. All arrays have the same number of values: $namesArr, $folderArr, $updatedAt, $valuesArr . I would like my new array to be contain:

$namesArr[0], $folderArr[0], $updatedAt[0], $valuesArr[0],
$namesArr[1], $folderArr[1], $updatedAt[1], $valuesArr[1],
$namesArr[2], $folderArr[2], $updatedAt[2], $valuesArr[2],
...

I guess the solution is pretty simple, but I got stuck :( Can anyone help?

Answer 1

You can use foreach loop to merge 4 arrays:

foreach ($namesArr as $key => $value) {
    $arr[$key][] = $value;
    $arr[$key][] = $folderArr[$key];
    $arr[$key][] = $updatedAt[$key];
    $arr[$key][] = $valuesArr[$key];
}

Thus $arr will be the merged array

Answer 2

我会做类似的事情：

$arr = array_map(function () { return func_get_args(); },$namesArr, $folderArr, $updatedAt, $valuesArr);

Answer 3

do the following way:

while($db->query($sql)){
$namesArr[] =$db->f('names');
$folderArr[]=$db->f('folder');
$updatedAt[]=$db->f('updated');
$valuesArr[]=$db->f('values');
}

Answer 4

<?php
$newArr = array();
for ($i = 0; $i < count($namesArr); $i++)
{
    $newArr[$i][0] = $namesArr[$i];
    $newArr[$i][1] = $folderArr[$i];
    $newArr[$i][2] = $updatedAt[$i];
    $newArr[$i][3] = $valuesArr[$i];
}
?>

Explanation

What this will do is iterate depending on how many elements there are in $namesArr .

I utilised a multidimensional array here so that the first set of square brackets is effectively the "row" in a table, and the second set of square brackets are the "column" of a table.