它不会更新或更改数据库

Question

How can I update multiple columns in the table? It doesnt change the data in the database.

<?php
$id = $_GET['user'];
$any = mysql_query("SELECT * FROM function WHERE id='".$id ."'");
if ($edit = mysql_fetch_assoc($any)){
?>

//this is the form for the input type when updating the column

<form action="reserve_event.php" method="POST">
    <input type="text" name="fh" value="<?php echo $edit['fh'];?>">
    <input type="text" name="package" value="<?php echo $edit['package'];?>">
    <input type="text" name="guest" value="<?php echo $edit['guest'];?>">
    <input type="text" name="fee" value="<?php echo $edit['fee'];?>">
    <input type="text" name="status" value="<?php echo $edit['status'];?>">
    <input type="submit" name="submit" value="submit">
</form>

//this part is when i submit the data.
<?php
}
if(isset($_POST['submit'])){
    $fh= $_POST["fh"];
    $package= $_POST["package"];
    $guest= $_POST["guest"];
    $fee = $_POST["fee"];
    $status= $_POST["status"];
    $sql1 = mysql_query("UPDATE function SET fh='".$fh."',package= '".$package."', guest = '".$guest."',fee = '".$fee."',status= '".$status."' WHERE id='".$id."'");
}
?>

Answer 1

You can try with blow given code:

<?php
if(isset($_POST['submit']))
{
    $fh= $_POST["fh"];
    $package= $_POST["package"];
    $guest= $_POST["guest"];
    $fee = $_POST["fee"];
    $status= $_POST["status"];
    $sql1 = mysql_query("UPDATE `function` SET `fh`='".$fh."',`package`= '".$package."', `guest` = '".$guest."',`fee` = '".$fee."',`status`= '".$status."' WHERE `id`='".$id."'");
}
?>

Answer 2

You are using a reserved word "function" for mysql for your table name, one or your columns name "status" is a reserved word too. This means that mysql server will read function and will try to execute it instead of choosing the table with that name. IMHO it is better not to use reserved words in table or column definition but you can use backticks ` to escape the names.

This link will provide you a list of reserved words. So just adapt your query this way:

$sql1 = mysql_query("UPDATE `function` 
SET fh='$fh',package= '$package', guest = '$guest',fee = '$fee', `status`= '$status' 
WHERE id='$id'");

Check with the link I provided you if you have more reserved words in your query

The same applies to the Select query:

$any = mysql_query("SELECT * FROM `function` WHERE id='$id'");

Also as I mentioned in my comments: your code is open to SQL injections: use prepared statements to sanitize user inputs. Mysql_* API is deprecated and removed in PHP 7. Move to mysqli or better PDO