[英]Pivot table to get data to be displayed like this?
Bit of an SQL newbie here. SQL新手介绍。 I have an SQL table which stores data at specific dates for a specific unique identifier.
我有一个SQL表,该表在特定日期存储特定唯一标识符的数据。
Example: 例:
UniqueIdentifier someData1 Date1 SomeData2 Date2 SomeData3 Date3
1 1000 01/01/2017 2000 01/02/2017 2000 01/03/2017
2 2000 21/01/2017 2500 21/02/2017 3540 21/03/2017
3 3000 05/01/2017 3000 08/07/2016 3000 12/05/2016
I would like to somehow convert the data so it ends up like this: 我想以某种方式转换数据,使其最终像这样:
UniqueIdentifier Data Date
1 1000 01/01/2017
1 2000 01/02/2017
1 2000 01/03/2017
2 2000 21/01/2017
2 2500 21/02/2017
2 3540 21/03/2017
3 3000 05/01/2017
3 3000 08/07/2016
3 3000 12/05/2016
Basically extracting each date and it's corresponding value into a separate line. 基本上将每个日期及其对应的值提取到单独的行中。 I'm guessing I need to use some sort of pivot table to do this, but I'm not quite sure exactly how to do it!
我猜想我需要使用某种类型的数据透视表来执行此操作,但是我不太确定该怎么做! Any help would be greatly appreciated!
任何帮助将不胜感激!
Using Union 使用联盟
select UniqueIdentifier, someData1 as 'Data', Date1 as 'Date' from <yourtable>
union
select UniqueIdentifier, someData2 as 'Data', Date2 as 'Date' from <yourtable>
union
select UniqueIdentifier, someData3 as 'Data', Date3 as 'Date' from <yourtable>
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