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jq提取密钥对的值并分配给bash变量

[英]jq extract value of keypair and assign to bash variable

jq does my head in sometimes. jq有时会引起我的注意。 Assume you have a json file called emails.json that looks like this; 假设您有一个名为emails.json的json文件,看起来像这样;

[
  {
    "ParameterKey": "foo1",
    "ParameterValue": "bar1"
  },
  {
    "ParameterKey": "foo2",
    "ParameterValue": "bar2"
  }
]

If I run my bash script (let's call it script.sh ) using the argument foo1, I want to have bar1 assigned to a variable called emailAdd . 如果我使用参数foo1运行bash脚本(我们称其为script.sh ),我希望将bar1分配给名为emailAdd的变量。 Likewise, if I use the argument foo2, I want bar2 assigned. 同样,如果我使用参数foo2,则希望分配bar2。

I thought my script would look like the following, but I'm getting an empty variable. 我以为我的脚本如下所示,但是我得到了一个空变量。

#!/usr/bin/env bash

EMAIL=$1

emailAdd=$(jq --arg email "$EMAIL" '.[] | select(.ParameterKey=="$email") | .ParameterValue' < emails.json)

echo "address is " $emailAdd 

So, running sh script.sh foo1 I would expect address is bar1 , etc 因此,运行sh script.sh foo1我希望address is bar1 ,等等

You pretty much have it correct. 您几乎正确了。 You don't need the quotes around $email , because unlike shell, jq actually treats that as a variable containing a value, rather than something to expand to arbitrary text. 您不需要$email周围的引号,因为与shell不同, jq实际上将其视为包含值的变量,而不是扩展为任意文本的变量。 You probably also want to use the -r option so that the output is bar1 , rather than "bar1" . 您可能还希望使用-r选项,以便输出为bar1而不是"bar1"

#!/usr/bin/env bash

EMAIL=$1

emailAdd=$(jq -r --arg email "$EMAIL" '.[] | select(.ParameterKey==$email) | .ParameterValue' < emails.json)

echo "address is $emailAdd" 

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