PHP / MYSQLI错误：注意：试图获取非对象的属性

Question

I am trying to echo an entire table from a database, but everytime I try to fix the 'Notice: Trying to get property of non-object in /home/st359450/public_html/epw/database.php on line 24' error, it won't work. In my browser I have confirmation that the connection to the database is working.

The PHP code after establishing the connection is:

<?php

$servername = "localhost";
$username = "359450";
$password = "dJDgxR";


//create connection


$conn = mysqli_connect($servername, $username, $password);

if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}

echo "Connected successfully <br> <br>";


$sql = "SELECT klantnummer, voornaam, tussenvoegsel, achternaam, straat, huisnummer, postcode, woonplaats, telefoonnummer, emailadres FROM CMI_klanten";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
    echo "Klantnummer: " . $row["klantnummer"] . "Naam: " . $row["voornaam"]. " " . $row["tussenvoegsel"]. " " . $row["achternaam"] . "Adres: " . $row["straat"] . " " . $row["huisnummer"] . " " . $row["woonplaats"] . "Telefoonnummer: " . $row["telefoonnummer"] . "Emailadres: " . $row["emailadres"] . "<br>";
}
} else {
echo "0 results";
}
$conn->close();

?>

Everything in the $sql variable is spelled correctly. I have checked it multiple times. Even though the error is displayed, it still outputs '0 results'. I have checked multiple similar questions, but none of them were able to fix my problem. The error is in the following bit:

 if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
    echo "Klantnummer: " . $row["klantnummer"] . "Naam: " . $row["voornaam"]. " " . $row["tussenvoegsel"]. " " . $row["achternaam"] . "Adres: " . $row["straat"] . " " . $row["huisnummer"] . " " . $row["woonplaats"] . "Telefoonnummer: " . $row["telefoonnummer"] . "Emailadres: " . $row["emailadres"] . "<br>";
}
} else {
echo "0 results";
}
$conn->close();

?> 

I hope you guys can help me!

Answer 1

You are calling object methods from a procedural mysqli. While I dont think this will break anything, for your own sanity and anyone who might see this code after you, I would pick one style and go with it consistently.

You cannot call num_rows immediately. Per the manual :

The use of mysqli_stmt_num_rows() depends on whether or not you used mysqli_stmt_store_result() to buffer the entire result set in the statement handle.

Add this line after your query call and try again:

$result->store_result(); 

Answer 2

You don't have a database parameter. Enter your database value as the last parameter when initializing the mysqli connection:

$database ='database_naam';

$conn = mysqli_connect($servername, $username, $password, $database);