[英]Assign a sub class to an interface, with generics and covariant involved
I defined 3 interfaces: 我定义了3个接口:
public interface IManufacturerInput
{
}
public interface IManufacturerOutput
{
}
public interface IManufacturerApi<in S, out T>
where S : IManufacturerInput
where T : IManufacturerOutput
{
T Calculate(S);
}
And I defined a specific Manufacturer: 我定义了一个特定的制造商:
public class ManufacturerAInput : IManufacturerInput
{
}
public class ManufacturerAOutput : IManufacturerOutput
{
}
public class ManufacturerAApi : IManufacturerApi<ManufacturerAInput, ManufacturerAOutput>
{
public ManufacturerAOutput Calculate(ManufacturerAInput)
{
return null;
}
}
And In Main() I created a ManufacturerAApi, and try assign it to IManufacturerApi. 在Main()中,我创建了一个ManufacturerAApi,然后尝试将其分配给IManufacturerApi。
IManufacturerApi<IManufacturerInput, IManufacturerOutput> api = new ManufacturerAApi();
But it failed. 但是失败了。 The error message said (just abstract meaning): 错误消息说(只是抽象含义):
Can't convert from ManufacturerAApi to IManufacturerApi<IManufacturerInput, IManufacturerOutput>
So is there any way I can make the assignment work? 那么,有什么方法可以使作业生效? Thanks in advance. 提前致谢。
What you are proposing isn't type safe. 您提议的内容类型不安全。 Let's change the names of your types to make the issue clearer: 让我们更改类型的名称,以使问题更清楚:
public interface IPetFood { }
public interface IPetSound { }
public interface IPetCage<in S, out T>
where S : IPetFood
where T : IPetSound
{
T Feed(S s);
}
public class DogFood : IPetFood { }
public class CatFood : IPetFood { }
public class Bark : IPetSound { }
public class DogCage : IPetCage<DogFood, Bark>
{
public Bark Feed(DogFood input)
{
return new Bark();
}
}
And now suppose this is legal: 现在假设这是合法的:
IPetCage<IPetFood, IPetSound> api = new DogCage();
Then we could do the following: 然后,我们可以执行以下操作:
api.Feed(new CatFood()); //oops we've just given the dog some catfood.
The assignment will not work because S
is contravariant, which means that any possible IPetFood
passed into api.Feed
would need to be a subtype of DogFood
and you have the opposite; 分配将不起作用,因为S
是反IPetFood
,这意味着传递给api.Feed
任何可能的IPetFood
必须是DogFood
的子类型,而您却相反。 IPetFood
is a superset of DogFood
. IPetFood
是的超集DogFood
。
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