[英]Javascript regex selecting numbers that are not connected to letters
This is my current regex: 这是我当前的正则表达式:
var re = '/\d+\s+[\d+a-z]+/gi';
I'm trying to get my regex to select numbers before if there are there own and then any abc characters and numbers after a whitespace 我正在尝试让我的正则表达式在出现空格之前先选择数字,然后在空格后选择任何abc字符和数字
This is my test string 这是我的测试字符串
part1 6
22 part2
part3 8
At the moment its selecting the following 目前其选择以下内容
1 : 6
22 part2
3 8
But I just want to be selecting this 但我只想选择这个
22 part2
So i'm only wanting to select this if the number is on its own. 所以我只想选择这个,如果数字是单独的。
Any help thanks ? 任何帮助谢谢吗?
The regex is /^\\d+\\s[a-zA-Z0-9]+$/
正则表达式为
/^\\d+\\s[a-zA-Z0-9]+$/
^
start ^
开始 \\d+\\s
1 or more digits and 1 space \\d+\\s
1个或多个数字和1个空格 [a-zA-Z0-9]+
the alpha numeric combination [a-zA-Z0-9]+
字母数字组合 $
end $
结束 var arr=["part1 6","22 part2","part3 8"]; var re=/^\\d+\\s[a-zA-Z0-9]+$/; arr.forEach(x => console.log(x,re.test(x)));
你可以试试这个正则表达式
regex : /^\d+\s[a-zA-Z0-9]+\s\d+$;
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.