Scala如何将Seq [（（（A，B，C，D），Seq [（E，F，G）]）]]转换为Seq [（A，B，C，D，Seq [（E，F，G） ]）]？
[英]Scala How to transform Seq[((A, B, C, D), Seq[(E, F, G)])] to Seq[(A, B, C, D, Seq[(E, F, G)])]?
问题描述
I'd like to transform the following sequence. 
我想转换以下顺序。
Seq[((A, B, C, D), Seq[(E, F, G)])]
to 至
Seq[(A, B, C, D, Seq[(E, F, G)])]
Could anyone kindly suggest a solution? 有人可以提出解决方案吗？
Thanks! 谢谢！
1 个解决方案
解决方案1
6 已采纳 2017-03-30 14:50:52
Simply: 只是：
val original: Seq[((A, B, C, D), Seq[(E, F, G)])] = ...
val res: Seq[(A, B, C, D, Seq[(E, F, G)])] =
original.map { case ((a, b, c, d), seq) => (a, b, c, d, seq) }
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