[英]php or javascript session rules popup
I just created a Pup-up using Magnific Pop-up. 我刚刚使用Magnific Pop-up创建了一个Pup-up。 I now have to set the session rules:
我现在必须设置会话规则:
The popup has to appear 5 seconds after the user lands in the website and has not to be shown for the rest of session 用户登陆网站后,弹出窗口必须显示5秒钟,其余的会话均不显示
The popup has to appear 5 times for each user's session: as soon as the user does not perform any action on the popup or the user closes the popup 5 times, the popup doesn't have to appear anymore. 每个用户会话的弹出窗口必须出现5次:只要用户不对弹出窗口执行任何操作,或者用户关闭弹出窗口5次,则不再必须出现弹出窗口。
Can you help me please? 你能帮我吗? Thanks in advance!
提前致谢!
Below is a simple solution, however depending on how your site is set up other page loads and/or ajax calls could increment the counter, so be conscious of when/where you increment the session variable $_SESSION['show_popup_count']
以下是一个简单的解决方案,但是根据您网站的设置方式,其他页面加载和/或ajax调用可能会增加计数器,因此请注意何时/何地增加会话变量
$_SESSION['show_popup_count']
<?php
session_start();
if(isset($_SESSION['show_popup_count'])){
//handle completely new session here
$_SESSION['show_popup_count']=0;
}
$_SESSION['show_popup_count'] += 1;
//expose value to javascript
?><script type="text/javascript">
var popupCounts = <?php echo $_SESSION['show_popup_count']; ?>;
</script><?php
.... //continue on with rest of code
then here is your additional javascript 然后这是您的其他JavaScript
if(popupCounts<6){
//code to show popup here
}
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