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如何随机访问所有数组而不重复

[英]how to visit all the array randomly without repeating

I have a SVG with more than a 1000 polygons each 3 look like a cube. 我有一个SVG,其中有1000多个多边形,每个3个看起来像一个立方体。 at the moment I'm changing the colour by class name. 目前,我正在按类别名称更改颜色。 but I would like that each polygon is visited randomly without any repeating, unit all of polygons visited. 但是我希望每个多边形都是随机访问的,没有任何重复,将所有访问的多边形单元化。

 https://jsfiddle.net/MSTq/rbgmjqwd/2/

for better view please visit jsfiddle 更好的观点,请访问jsfiddle

 /* Created on : 11/03/2017, 7:01:53 PM Author : MSTq */ $(document).ready(function(){ var polygons = $("#Layer_1").find("polygon"); /*var paths = $("#svg-layer-1 ").find("path"); var pathslength = paths.length;*/ var polygonslength = polygons.length; var colorSeter = $("#curent-color-set").find(".color-set"); var byclass = []; for(var f = 0 ; f < 9; f++){ byclass.push($("#Layer_1").find(".st" + f)); } setInterval(function (){ var clor = rColorSet([rColor(),rColor()])[randomise(2,0)]; var rar = randomise(8,0); var colrSeter = colorSeter[rar]; byclass[rar].css({"fill":clor,"stroke":clor}); $(colrSeter).css({"background-color":clor}); $("#" + $(colrSeter).attr("id") + " p").text(clor); },500); }); function isPositive (){ return arguments[0] > 0; } function vlidPositive (){ return isPositive(arguments[0]) ? arguments[0] : 0; } function comparer (){ return arguments[0] > arguments[1]; } function reservation (r,t){ r = vlidPositive(arguments[0]), t = vlidPositive(arguments[1]); return (r * t) / 100; } function randomise (max,min){ max = vlidPositive(arguments[0]),min = vlidPositive(arguments[1]); return Math.floor(Math.random() * (max - min + 1)) + min; } function rColor (){ var hex = ["0","1","2","3","4","5","6","7","8","9","A","B","C","D","E","F"], hexLength = hex.length -1, limits = [[11,4], [12,6], [hexLength,8]], color = "", final = "#", temp = ""; for (var j =0 ; j < 3; j++){ for (var i = 0 ; i < 2; i++){ temp += hex[randomise(limits[j][0] , limits[j][1])]; } color += temp; temp = ""; } final += color; return final; } function rColorSet(){ var colorset = []; for (var i = 0; i < arguments.length; i++) { if (Array.isArray(arguments[i])){ colorset = arguments[i]; break; } } return colorset; } 
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"/> <polygon id="XMLID_116_" class="st5" points="519.6,449.5 476.3,424.5 476.3,426.3 476.3,424.5 433,449.5 476.3,474.5 "/> <polygon id="XMLID_115_" class="st6" points="562.9,524.5 562.9,474.5 519.6,449.5 519.6,499.5 "/> <polygon id="XMLID_114_" class="st7" points="519.6,499.5 519.6,499.5 476.3,524.5 519.6,549.5 562.9,524.5 562.9,524.5 "/> <polygon id="XMLID_113_" class="st8" points="519.6,499.5 518.5,498.8 519.6,499.5 519.6,449.5 476.3,474.5 476.3,524.5 519.6,499.5 "/> </g> <g id="XMLID_252_"> <polygon id="XMLID_261_" class="st0" points="-86.6,449.5 -129.9,474.5 -129.9,524.1 -86.6,499.3 "/> <polygon id="XMLID_260_" class="st1" points="-86.6,499.3 -129.9,524.1 -129.9,524.5 -86.6,549.5 -43.3,524.5 -86.6,499.5 "/> <polygon id="XMLID_259_" class="st2" points="-86.6,449.5 -86.6,499.3 -84.5,498.1 -86.6,499.3 -86.6,499.5 -43.3,524.5 -43.3,474.5 "/> <polygon id="XMLID_258_" class="st3" points="0,449.5 0,399.5 -43.3,374.5 -43.3,424.5 "/> <polygon id="XMLID_257_" class="st4" points="-43.3,374.5 -86.6,399.5 -86.6,449.5 -43.3,424.5 "/> <polygon id="XMLID_256_" class="st5" points="0,449.5 -43.3,424.5 -43.3,426.3 -43.3,424.5 -86.6,449.5 -43.3,474.5 "/> <polygon id="XMLID_255_" class="st6" points="43.3,524.5 43.3,474.5 0,449.5 0,499.5 "/> <polygon id="XMLID_254_" class="st7" points="0,499.5 0,499.5 -43.3,524.5 0,549.5 43.3,524.5 43.3,524.5 "/> <polygon id="XMLID_253_" class="st8" points="0,499.5 -1.1,498.8 0,499.5 0,449.5 -43.3,474.5 -43.3,524.5 0,499.5 "/> </g> </svg> 

It looks like the polygons have unique ids? 多边形看起来有唯一的ID? For example: XMLID_121_ 例如:XMLID_121_

If so, maybe you could do something like this: 1) Put all of the polygon ids in an array 2) randomly visit a location in the array 3) do something with the element in that array location ("visit the polygon with that id", etc.) 4) extract the visited array element from the array 5) keep doing this until there are no elements left in the id array. 如果是这样,也许您可​​以执行以下操作:1)将所有多边形ID放入数组中2)随机访问数组中的某个位置3)对该数组位置中的元素进行一些操作(“访问具有该ID的多边形(等)。4)从数组中提取访问的数组元素5)继续执行此操作,直到id数组中没有元素为止。

Here is a simple JavaScript program to that effect: 这是一个简单的JavaScript程序:

var polygonIds = [1, 2, 3, 4, 5]; //the order doesn't matter
while (polygonIds.length > 0) { //repeat until no more elements left
   var position = Math.floor(Math.random() * polygonIds.length); //choose random location
   var extracted = polygonIds[position]; //get that element
   alert(extracted); //do whatever you want to do with the extracted element
   polygonIds.splice(position, 1); //remove the element from array
}

Maybe there is a better way to do this. 也许有更好的方法可以做到这一点。 But it seems reasonable, and it looks like you are using JavaScript. 但这似乎是合理的,并且看起来您正在使用JavaScript。 So something like this might work for you. 因此,这样的事情可能对您有用。

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