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laravel中的数组到字符串转换

[英]array to string conversion in laravel

I am trying to fetch some data from table in laravel 5.0 like so 我试图从laravel 5.0中的表中获取一些数据

public function index()
    {
        $data = DB::table('modules')->get();

        return view("BaseView.home")->with('data',$data);
    }

this is my view 这是我的看法

 @foreach($data as $modules)
    <li class="nav-item dropdown">
        <a class="nav-link dropdown-toggle" href="#" id="navbarDropdownMenuLink" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
            {{ $modules->module_name }}<i class="plusMinus fa fa-plus-square plusMinusSpacing" aria-hidden="true"></i>
        </a>
        <div class="dropdown-menu" aria-labelledby="navbarDropdownMenuLink">
            {!! $moduleCategories = DB::table('module_categories')->where('modules_id','=',$modules->id)->get() !!}
            @foreach($moduleCategories as $category)
            <a class="dropdown-item" href="#">{{ $category->categories_name }}</a>
            @endforeach
        </div>
    </li>
    @endforeach

$module->id is obtained from another query result. $ module-> id从另一个查询结果中获取。 Now when I try to run this I am getting Array to string conversion . 现在,当我尝试运行它时,我得到Array to string conversion Can someone point out the mistake. 有人可以指出错误。 The expected output is > 1 in the sense there can be multiple categories names matching that condition. 在某种意义上,预期输出> 1,可以有多个类别名称匹配该条件。

The problem is that you are trying to put php logic inside an echo {{ ... }} . 问题是你试图将php逻辑放在echo {{ ... }} You are trying to echo out a collection or an array of data, hence the error you are getting, Array to string conversion . 您正在尝试回显一个集合或数组,因此您将获得错误, Array to string conversion The proper way to do this is to do the logic in the controller. 正确的方法是在控制器中执行逻辑。 But for a quick fix, replace: 但要快速解决,请更换:

{!! $moduleCategories = DB::table('module_categories')->where('modules_id','=',$modules->id)->get() !!}

to

<php $moduleCategories = DB::table('module_categories')->where('modules_id','=',$modules->id)->get(); ?>

Never use {{ ... }} or {!! ... !!} 永远不要使用{{ ... }}{!! ... !!} {!! ... !!} to put logic, those are to echo out a string. {!! ... !!}放置逻辑,那些是回显出一个字符串。

==EDIT== == ==编辑

I suggest to use laravels eloquent relationship methods, this will simplify the code, and seperate the logic from the view. 我建议使用laravels雄辩的关系方法,这将简化代码,并从视图中分离逻辑。

Note: Expecting if you are using laravel naming convention. 注意:期望您是否使用laravel命名约定。

On your Modules model, add a relationship to ModuleCategory like so: Modules模型上,添加一个与ModuleCategory的关系,如下所示:

public function module_categories()
{
    return $this->hasMany('App\ModuleCategory');
}

On your controller, on the index method replace : 在您的控制器上,在索引方法上替换:

$data = DB::table('modules')->get();

with

$data = Modules::get();

and finally on the view, change it like so: 最后在视图上,改变它:

@foreach($data as $modules)
<li class="nav-item dropdown">
    <a class="nav-link dropdown-toggle" href="#" id="navbarDropdownMenuLink" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
        {{ $modules->module_name }}<i class="plusMinus fa fa-plus-square plusMinusSpacing" aria-hidden="true"></i>
    </a>
    <div class="dropdown-menu" aria-labelledby="navbarDropdownMenuLink">
        @foreach($modules->module_categories as $category)
        <a class="dropdown-item" href="#">{{ $category->categories_name }}</a>
        @endforeach
    </div>
</li>
@endforeach

As I commented on Carlos's solution, here is how I solved the same error... 正如我对卡洛斯的解决方案发表评论,以下是我如何解决同样的错误......

//Controller
$users  = User::where('blah', 'blah')->get();
return view('index', [
   'users'  => $users,
]);


//View
<script type="text/javascript">
  angular.module("app").factory("DataService", function() {
    return {
      users: {!! $users !!},
    };
 });
</script>

As discussed above, this will result in the Array to string conversion error, since $users is an array. 如上所述,这将导致Array to string conversion错误,因为$users是一个数组。

However, this error won't happen if $users is a `collection' 但是,如果$users是“集合”,则不会发生此错误

Ie

//Controller
$users  = User::all();
return view('index', [
   'users'  => $users,
]);
//This is ok

Or, 要么,

//Controller
$users  = collect([]);
return view('index', [
   'users'  => $users,
]);
//This is fine too

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