[英]Conditionally set a object property
Its possible to remove the .where clause if queryString is null? 如果queryString为null,可以删除.where子句吗?
I have tried ternary operator in the middle of expression, but doesn't work. 我在表达式中尝试了三元运算符,但不起作用。
Also the equals expression dont allow: null, undefined or empty String. 此外,equals表达式不允许:null,undefined或empty String。
CashierHistory
.scan()
.where('userId').equals(path['userId'])
.where('status').equals(queryString['status']) # remove all this line in case of queryString['status'] is null
.limit(10)
.startKey(queryString)
.exec(function (err, acc) {
if (err == null) {
console.log(acc);
return cb(null, Api.response(acc));
} else {
console.log(err['message']);
return cb(null, Api.errors(200, {5: err['message']}));
}
});
Edit : I am using Dynogels (An ORM for Dynamodb) 编辑 :我正在使用Dynogels (一个ORM for Dynamodb)
As dandavis said you can break your query into two parts 正如dandavis所说,你可以将你的查询分为两部分
var query = CashierHistory
.scan()
.where('userId').equals(path['userId']);
if (queryString['status']) {
query = query.where('status').equals(queryString['status']);
}
return query.limit(10)
.startKey(queryString)
.exec(function (err, acc) {
if (err == null) {
console.log(acc);
return cb(null, Api.response(acc));
} else {
console.log(err['message']);
return cb(null, Api.errors(200, {5: err['message']}));
}
});
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