从列表元素中删除数字

Question

I have a list of job titles (12,000 in total) formatted in this way:
Career_List = ['1) ABLE SEAMAN', '2) ABRASIVE GRADER', '3) ABRASIVE GRINDER']

How do I remove the numbers, parentheses, and spaces from the list elements so that I end up with this output:
Career_List_Updated = ['ABLE SEAMAN', 'ABRASIVE GRADER', 'ABRASIVE GRINDER']

I know that I am unable to simply remove the first three characters because I have more than ten items in my list.

Answer 1

利用str.lstrip()和其余strip函数接受多个字符作为参数的事实。

Career_List_Updated =[career.lstrip('0123456789) ') for career in Career_List]

Answer 2

Split each career at the first space; keep the rest of the line.

Career_List = ['1) ABLE SEAMAN', '2) ABRASIVE GRADER', '3) ABRASIVE GRINDER', '12000) ZEBRA CLEANER']
Career_List_Updated = []

for career in Career_List:
    job = career.split(' ', 1)
    Career_List_Updated.append(job[1])

print Career_List_Updated

Output:

['ABLE SEAMAN', 'ABRASIVE GRADER', 'ABRASIVE GRINDER', 'ZEBRA CLEANER']

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One-line version:

Career_List_Updated = [career.split(' ', 1)[1] \
                       for career in Career_List]

Answer 3

We want to find the first index that STOPS being a bad character and return the rest of the string, as follows.

def strip_bad_starting_characters_from_string(string):
    bad_chars = set(r"'0123456789 )") # set of characters we don't like
    for i, char in enumerate(string):
        if char not in bad_chars
            # we are at first index past "noise" digits
            return string[i:]

career_list_updated = [strip_bad_starting_characters_from_string(string) for string in career_list]