Python Access odbc，应跳过该行

Question

I am using MS Access to import the table information. Table is below:

Field1   Field2
U1a14    High Speed Link
U0001    Medium speed data
U0022    Low Speed Link 

My code value is like: code = U1a14 code = U0001 code = B11DB (This code is not present in table)

I am connecting to odbc and searching for code in table.

connection = pypyodbc.connect('DRIVER={Microsoft Access Driver (*.mdb)};UID=admin;UserCommitSync=Yes;SafeTransactions=0;MaxScanRows=8;MaxBufferSize=2048;FIL={MS Access};DriverId=25;DefaultDir=C:\PYTHON27;DBQ=C:\PYTHON27\iso14229dtcs.mdb;')
cursor1 = connection.cursor()
cursor1.execute("SELECT Field2 FROM Table Where Field1 = '{}'".format(code))

for row in cursor1.fetchone():
  print row

I am getting error:

error:
for row in cursor1.fetchone():
TypeError: 'NoneType' object is not iterable

How Can I fix it, If the code is not present in my Table, it should skip and print only existing row

Answer 1

Change the code to the following, check cursor1.fetchone() is not NULL.

    connection = pypyodbc.connect('DRIVER={Microsoft Access Driver (*.mdb)};UID=admin;UserCommitSync=Yes;SafeTransactions=0;MaxScanRows=8;MaxBufferSize=2048;FIL={MS Access};DriverId=25;DefaultDir=C:\PYTHON27;DBQ=C:\PYTHON27\iso14229dtcs.mdb;')
    cursor1 = connection.cursor()
    cursor1.execute("SELECT Field2 FROM Table Where Field1 = '{}'".format(code))
    row = cursor1.fetchone()
    while row is not None:
        print row[0], row[1]
        row = cursor1.fetchone()
    cursor1.close()
    connection.close()