[英]Circe cannot find implicit encoder
I am trying to encode a few classes into json strings, however no matter what I try, my classes do not seem to be able to find an implicit encoder for the case classes I am using. 我试图将几个类编码为json字符串,但无论我尝试什么,我的类似乎都找不到我正在使用的case类的隐式编码器。
Here's the smallest example I was able to pare it down to. 这是我能够减少的最小的例子。
import io.circe._
import io.circe.generic.semiauto._
import io.circe.generic.auto._
import io.circe.syntax._
case class OneCol(value: String)
object testObject {
def main(args: Array[String]): Unit = {
val testVal = OneCol("someVal")
println(testVal.asJson)
}
}
Which gives the following compile error 这给出了以下编译错误
Error:(30, 21) could not find implicit value for parameter encoder: io.circe.Encoder[OneCol] println(testVal.asJson)
错误:(30,21)找不到参数编码器的隐含值:io.circe.Encoder [OneCol] println(testVal.asJson)
I have tried the same thing with semi-auto encoder creation 我用半自动编码器创建尝试了同样的事情
def main(args: Array[String]): Unit = {
implicit val enc : Encoder[OneCol] = deriveEncoder
val testVal = OneCol("someVal")
println(testVal.asJson)
}
Which gives the following errors 这给出了以下错误
Error:(25, 42) could not find Lazy implicit value of type io.circe.generic.encoding.DerivedObjectEncoder[A] implicit val enc : Encoder[OneCol] = deriveEncoder
错误:(25,42)找不到类型为io.circe.generic.encoding的延迟隐式值.DerivedObjectEncoder [A]隐式val enc:Encoder [OneCol] = deriveEncoder
Error:(25, 42) not enough arguments for method deriveEncoder: (implicit encode: shapeless.Lazy[io.circe.generic.encoding.DerivedObjectEncoder[A]])io.circe.ObjectEncoder[A].
错误:(25,42)方法deriveEncoder没有足够的参数:(隐式编码:shapeless.Lazy [io.circe.generic.encoding.DerivedObjectEncoder [A]])io.circe.ObjectEncoder [A]。 Unspecified value parameter encode.
未指定的值参数编码。 implicit val enc : Encoder[OneCol] = deriveEncoder
隐式val enc:Encoder [OneCol] = deriveEncoder
I am fairly sure that the entire purpose of auto and semi-auto encoder generation is to handle situations like these, so I am at a bit of a loss as to what I am doing wrong. 我很确定自动和半自动编码器生成的整个目的是处理这样的情况,所以我对我做错了什么感到有点失落。
I am using scala 2.10.4, and circe 0.7.0 (circe-core_2.10, circe-generic_2.10 artifacts) if version information is relevant, with maven as the package manager. 如果版本信息相关,我使用scala 2.10.4和circe 0.7.0(circe-core_2.10,circe-generic_2.10工件),maven作为包管理器。
Does anyone know why this is failing, and how to get it properly compiling? 有谁知道为什么这是失败的,以及如何正确编译?
Edit: 编辑:
Here's the section of my POM with the macros plugin. 这是我的POM中带有宏插件的部分。 Have tried both compiler plugins listed (both commented and non-commented), and both still give the same error.
已经尝试了列出的两个编译器插件(注释和非注释),并且两者仍然给出相同的错误。
<plugin>
<groupId>net.alchim31.maven</groupId>
<artifactId>scala-maven-plugin</artifactId>
<configuration>
<args>
<!-- work-around for https://issues.scala-lang.org/browse/SI-8358 -->
<arg>-nobootcp</arg>
</args>
<recompileMode>incremental</recompileMode>
<compilerPlugins>
<compilerPlugin>
<groupId>org.scalamacros</groupId>
<artifactId>paradise_2.10.4</artifactId>
<version>2.1.0</version>
</compilerPlugin>
<!--<compilerPlugin>-->
<!--<groupId>org.scala-lang.plugins</groupId>-->
<!--<artifactId>macro-paradise_2.10.2</artifactId>-->
<!--<version>2.0.0-SNAPSHOT</version>-->
<!--</compilerPlugin>-->
</compilerPlugins>
</configuration>
<executions>
<execution>
<id>scala-compile-first</id>
<phase>process-resources</phase>
<goals>
<goal>compile</goal>
</goals>
</execution>
<execution>
<id>scala-test-compile-first</id>
<phase>process-test-resources</phase>
<goals>
<goal>testCompile</goal>
</goals>
</execution>
</executions>
</plugin>
It turns out that circe-core_2.10 has a dependency on scala version 2.10.6, meaning that my version of scala (2.10.4) was incompatible with the library, causing the issues. 事实证明,circe-core_2.10依赖于scala版本2.10.6,这意味着我的scala版本(2.10.4)与库不兼容,导致问题。 Upgrading to the proper version of scala fixed this.
升级到适当版本的scala修复了这个问题。
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