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Informatica数据类型转换

[英]Informatica datatype conversion

wanted to have two columns separate in target table 想要在目标表中将两列分开

  • Column: CTDATE in YYYYMMDD Format 列: YYYYMMDD格式的CTDATE
  • Column: CTTIME in HHMMSS Format. 列: HHMMSS格式的CTTIME。

How can I populate in Expression Transformation? 如何在“表达式转换”中填充? What is the expression used? 使用什么表达? Please guys, help me out. 拜托,帮帮我。

I used 我用了

  • TO_CHAR(in_column, 'YYYYMMDD') for CTDATE TODCHAR(in_column,'YYYYMMDD')for CTDATE
  • TO_CHAR(in_column, 'HHMISS') for CTTIME CTTIME的TO_CHAR(in_column,'HHMISS')

If your in_column type is already date/time then what you are using right now is almost correct, except use HH24MISS instead of HHMISS . 如果您的in_column类型已经是date/time那么您现在使用的几乎是正确的,除了使用HH24MISS而不是HHMISS Or use HH12MISS AM . 或使用HH12MISS AM

  • TO_CHAR(in_column, 'YYYYMMDD') for CTDATE TODCHAR(in_column,'YYYYMMDD')for CTDATE
  • TO_CHAR(in_column, 'HH24MISS') for CTTIME CTTIME的TO_CHAR(in_column,'HH24MISS')

If in_column is a string , the first convert it to a date/time . 如果in_columnstring ,则第一个将其转换为date/time Suppose in_column is coming as 'Jan 24 2017 14:24:56' then 假设in_column'Jan 24 2017 14:24:56'

  • first create a variable v_in_column as TO_DATE( in_column, 'MON DD YYYY HH24:MI:SS' ) 首先创建一个变量v_in_column作为TO_DATE( in_column, 'MON DD YYYY HH24:MI:SS' )
  • Then use this variable to derive CTDATE and CTTIME 然后使用此变量导出CTDATECTTIME
    • TO_CHAR(v_in_column, 'YYYYMMDD') for CTDATE CTDATE的TO_CHAR(v_in_column,'YYYYMMDD')
    • TO_CHAR(v_in_column, 'HHMISS') for CTTIME CTTIME的TO_CHAR(v_in_column,'HHMISS')

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