[英]Sub selects within MySQL query
I am wanting to alias 3 variables in my query, total_time_taken
and average
and request_count
. 我想在查询中给3个变量total_time_taken
别名,即total_time_taken
和average
和request_count
。
The average is meant to calculate the total_time_taken / request_count
to return average
however it is giving me a syntax error 该平均值用于计算total_time_taken / request_count
以返回average
但是它给了我一个语法错误
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'select(created_at, assigned_at, SUM(TIMESTAMPDIFF(SECOND, requests.created_at, r' at line 4
The query is below. 查询如下。
select
*,
COUNT(*) as request_count,
select(created_at, assigned_at, SUM(TIMESTAMPDIFF(SECOND, requests.created_at, requests.assigned_at)) from requests) as total_time_taken,
total_time_taken / request_count as average
from
`requests`
where
`deleted_at` is null
and
`submitted_at` >= '2017-03-30 00:00:00'
and
`requests`.`deleted_at` is null
group by
`engineer_id`
limit 5
I don't see the point of the subqueries, why not just take the sum as you aggregate by each engineer? 我看不到子查询的意义,为什么不随便由每个工程师汇总总和呢? Alse, you were doing SELECT *
with GROUP BY
, which usually doesn't work, and usually is wrong, because it would include non aggregate columns. 另外,您正在使用GROUP BY
进行SELECT *
,这通常不起作用,并且通常是错误的,因为它将包括非聚合列。 Instead, just select engineer_id
or an aggregate of some other column. 相反,只需选择engineer_id
或其他某些列的集合。
SELECT
engineer_id,
COUNT(*) AS request_count,
SUM(TIMESTAMPDIFF(SECOND, created_at, assigned_at)) AS total_time_taken,
SUM(TIMESTAMPDIFF(SECOND, created_at, assigned_at)) /
COUNT(*) AS average
FROM requests
WHERE deleted_at IS NULL AND
submitted_at >= '2017-03-30 00:00:00' AND
deleted_at IS NULL
GROUP BY engineer_id
LIMIT 5
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