查看字符串是否在C中包含子字符串

Question

I have the task of finding out if one of the many strings in my array contains an @ character.

Example -

I am @HOME or @SCHOOL

If the string does contain the @ i want to print out the string.

arr is declared as follows

char* arr[10][100];

I thought of using this

   if(strstr(arr[j], "@") != NULL);
   {
      printf("hey\n");
   }

but it prints out every single string whether or not they have the @.

Answer 1

Remove semicolon after the if condition. Like

if(strstr(outputArr[j], "@") != NULL)

Because

 if(strstr(outputArr[j], "@") != NULL);

is equivalent to

if(strstr(outputArr[j], "@") != NULL)
{

}

C99-6.8.3 paragraph 3:

A null statement (consisting of just a semicolon) performs no operations.