如何使用sed删除多行两个模式之间的内容？
[英]How do i remove the content between two patterns on multiple lines using sed?
问题描述
This is the input 
这是输入
hai people<PATTERN> we had
<PATTERN>a lot of fun<PATTERN>
writing scri pts
We will<PATTERN>
have more
<PATTERN>tomorrow<PATTERN>
Hurray!
Need to have 需要有
hai people<PATTERN> we had
writing scripts
We will<PATTERN>
have more
Hurray!
For me the first pattern match removes using the following command 对我来说，第一个模式匹配使用以下命令删除
sed '/PATTERN/{n;/PATTERN/d}' filename
1 个解决方案
解决方案1
3 2017-04-04 04:41:14
grep -Pv '^<PATTERN>.*<PATTERN>$' input
hai people<PATTERN> we had
writing scri pts
We will<PATTERN>
have more
Hurray!
using sed ,although its an overkill: 使用sed ，尽管这是一个过大的杀伤力：
sed '/^<PATTERN>.*<PATTERN>$/d' input
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