遍历指针到char指针数组

Question

Lets say I have the following code:

char *array[] = {"one", "two", "three"};
char *(*arrayPtr)[] = &array;

How do I iterate over array? I've tried doing this but doesn't work:

for(int i = 0; i < sizeof(array)/sizeof(array[0]); i++) {
    printf("%s\n", (*arrayPtr + i));
}

Answer 1

The scheme you have is missing a derference. *arrayPtr + i is the address of the i-th element of the array. Meaning it's a char** . You need to at least dereference that:

printf("%s\n", *(*arrayPtr + i));

However, that isn't valid C you have there, since you omitted the array size when defining the pointer. I hope it's not the actual code you wrote.

Also, note that you can use the subscript operator as Blagovest Buyukliev pointed out, but be weary of operator precedence. It's (*arrayPtr)[i] and not *arrayPtr[i] .