简体   繁体   English

不要在iOS对话框区域之外用轻击手势关闭uialertcontroller工作表

[英]Don't dismiss uialertcontroller sheet with tap gesture outside dialog area in iOS

in my iOS swift 3.0 application, I presented UIAlertController sheet instance over my current ViewController. 在我的iOS swift 3.0应用程序中,我在当前的ViewController上展示了UIAlertController表实例。 But I don't want to dismiss that sheet when I tapped on outside an area of the sheet (dimmed semi-transparent background) because I already have to cancel an action. 但是当我在表格的某个区域(变暗的半透明背景)之外点击时,我不想解散该表格,因为我已经必须取消一个动作。 Any idea? 任何想法?

I have MGSwipeTableViewCell with more button. 我有带有更多按钮的MGSwipeTableViewCell。 When User clicks on that "More" button, following code executes. 当用户单击该“更多”按钮时,将执行以下代码。

func onClickMore(for vmCell: VmCell) {
    let sheet = UIAlertController(title: vmCell.vmItem?.vmNameWithoutIp, message: vmCell.vmItem?.ipAddress, preferredStyle: .actionSheet)

    sheet.addAction(UIAlertAction(title: "Create Ticket", style: .default) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Start VM", style: .default) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Restart VM", style: .default) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Stop VM", style: .destructive) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Cancel", style: .cancel) { (action: UIAlertAction) in

    })

    present(sheet, animated: true) { 
        sheet.view.superview?.addGestureRecognizer(UITapGestureRecognizer(target: self, action: nil))
    }
}

for UIAlertController Type as alert 用于UIAlertController类型作为警报

you can download the sample project 您可以下载示例项目

add the gesture recognizer to alertController superview for handle the userinteraction 将手势识别器添加到alertController超级视图中以处理用户交互

self.present(alertController, animated: true, completion: {() -> Void in
 alertController.view.superview?.addGestureRecognizer(UITapGestureRecognizer(target: self, action: nil)
})

on that action do nothing 在那个动作上什么也不做

update 更新

let alertController = UIAlertController(title: "Do something", message: "With this", preferredStyle: .alert)
    alertController.addAction(UIAlertAction(title: "Done", style: .default) { action in
        // perhaps use action.title here
    })

    self.present(alertController, animated: true, completion: {() -> Void in


        alertController.view.superview?.addGestureRecognizer(UITapGestureRecognizer(target: self, action: nil))
    })

for UIAlertController Type as actionSheet 用于UIAlertController类型为actionSheet

you can download the sample project 您可以下载示例项目

you can do this two ways 你可以用两种方法

option 1 选项1

 alert.view.superview.subviews[0] isUserInteractionEnabled = false

option 2 选项2

   alert.view.superview?.subviews[0].addGestureRecognizer(UITapGestureRecognizer(target: self, action: nil))

for eg 例如

   self.present(sheet, animated: true, completion: {() -> Void in
    //    sheet.view.superview?.subviews[0].isUserInteractionEnabled = false;
      sheet.view.superview?.subviews[0].addGestureRecognizer(UITapGestureRecognizer(target: self, action: nil))

    })

full code 完整的代码

  let sheet = UIAlertController(title: "karthik", message: "check with", preferredStyle: .actionSheet)

    sheet.addAction(UIAlertAction(title: "Create Ticket", style: .default) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Start VM", style: .default) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Restart VM", style: .default) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Stop VM", style: .destructive) { (action: UIAlertAction) in

    })

    sheet.addAction(UIAlertAction(title: "Cancel", style: .cancel) { (action: UIAlertAction) in

    })



    self.present(sheet, animated: true, completion: {() -> Void in
    //    sheet.view.superview?.subviews[0].isUserInteractionEnabled = false;
      sheet.view.superview?.subviews[0].addGestureRecognizer(UITapGestureRecognizer(target: self, action: nil))

    })

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM