[英]Call static member function by pointer
I'm working on a small custom Assembler 我正在开发一个小型的定制汇编程序
I have a vector of struc to storing OPCODE informations (Mnemonic, number and type of argument, parsing function,...) 我有一个struc来存储OPCODE信息(助记符,参数的数量和类型,解析函数等)。
typedef char args_type_t;
typedef struct op_s {
std::string opcode;
char nbr_args;
args_type_t type[4];
int code;
Tryte (*fct)(std::vector<std::string>);
} op_t;
the parsing function is pointer on a static member function : 解析函数是静态成员函数上的指针:
{"MOV", 2, {T_REGISTER | T_ADDRESS, T_REGISTER | T_ADDRESS | T_CONSTANT}, 1, &Opcodes::MOV},
and the function : 和功能:
class Opcodes
{
public:
static Tryte Opcodes::MOV(std::vector<std::string> _opMap) {
return Tryte(0);
}
};
I try this, but I get SEGFAULT ( str()
is a member function of Tryte) : 我尝试了这个,但是得到了SEGFAULT(
str()
是Tryte的成员函数):
for (int i = 0; i < opMap.size(); i++) {
for (int j = 0; j < op_tab.size(); j++) {
if (!op_tab[j].opcode.compare(opMap[i][2])) {
std::cout << "OPBYTE : " << op_tab[j].fct(opMap[i]).str() << std::endl;
}
}
}
I want to call my function without instanciate Opcodes object it's posible ? 我想在没有可能的Opcodes对象的情况下调用我的函数吗?
EDIT : 编辑:
my error was here : if (!op_tab[j].opcode.compare(opMap[i][2]))
my mnemonic is the 1st item n opMap 我的错误在这里:
if (!op_tab[j].opcode.compare(opMap[i][2]))
我的助记符是opMap的第一项
Your code seems right, so perhaps a debugger information could help a bit. 您的代码似乎正确,因此调试器信息可能会有所帮助。 But we can try to improve the friendlyness of the code by using a std::function:
但是我们可以尝试使用std :: function来提高代码的友好性:
typedef char args_type_t;
#include <functional>
typedef struct op_s {
std::string opcode;
char nbr_args;
args_type_t type[4];
int code;
std::function<Tryte(std::vector<std::string>>)> fct;
} op_t;
As for the sefgault, send us the backtrace. 至于后悔,请给我们回溯。 Also, try to use range-based-for as it doesn't needs to tranverse the map to get the element again (as you are doing inside of the inner loop)
另外,请尝试使用基于范围的for,因为它不需要遍历地图即可再次获取元素(就像您在内部循环中所做的一样)
for (auto op : opMap) {
for (auto tab : op_tab) {
if (!tab.opcode.compare(op[1])) {
std::cout << "OPBYTE : " << tab.fct(op).str() << std::endl;
}
}
}
One common fix that you can do to not miss the indexes anymore is to use an Enum holding the possibilities. 您可以再做一次不丢失索引的常见解决方法是使用Enum来保持可能性。
enum Columns {
FuncPointer,
UserData
}
for (auto op : opMap) {
for (auto tab : op_tab) {
if (!tab.opcode.compare(op[FuncPointer])) {
std::cout << "OPBYTE : " << tab.fct(op).str() << std::endl;
}
}
}
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