简体   繁体   English

熊猫枢纽分析表

[英]pandas pivot table for heatmap

I am trying to generate a heatmap using seaborn, however I am having a small problem with the formatting of my data. 我正在尝试使用seaborn生成热图,但是我的数据格式存在一个小问题。

Currently, my data is in the form: 目前,我的数据格式为:

Name     Diag   Date
A        1       2006-12-01
A        1       1994-02-12
A        2       2001-07-23
B        2       1999-09-12
B        1       2016-10-12
C        3       2010-01-20
C        2       1998-08-20

I would like to create a heatmap (preferably in python) showing Name on one axis against Diag - if occured. 我想创建一个热图(最好在python中),以在与Diag一个轴上显示Name (如果发生)。 I have tried to pivot the table using pd.pivot , however I was given the error 我尝试使用pd.pivot旋转表,但是出现错误

ValueError: Index contains duplicate entries, cannot reshape ValueError:索引包含重复的条目,无法重塑

this came from: 来自:

piv = df.pivot_table(index='Name',columns='Diag') piv = df.pivot_table(index ='Name',columns ='Diag')

Time is irrelevant, but I would like to show which Names have had which Diag , and which Diag combos cluster together. 时间无关紧要,但是我想展示一下哪些Names具有哪些Diag以及哪些Diag组合在一起。 Do I need to create a new table for this or is it possible for that I have? 我是否需要为此创建一个新表? In some cases the Name is not associated with all Diag 在某些情况下, Name未与所有Diag相关联

EDIT: I have since tried: piv = df.pivot_table(index='Name',columns='Diag', values='Time', aggfunc='mean') 编辑:我从此尝试过:piv = df.pivot_table(index ='Name',columns ='Diag',values ='Time',aggfunc ='mean')

However as Time is in datetime format, I end up with: 但是,由于时间采用日期时间格式,因此我得出以下结论:
pandas.core.base.DataError: No numeric types to aggregate pandas.core.base.DataError:没有要聚合的数字类型

You need pivot_table with some aggregate function, because for same index and column have multiple values and pivot need unique values only: 您需要带有一些聚合函数的pivot_table ,因为对于相同的索引和列,它具有多个值,而pivot仅需要唯一的值:

print (df)
  Name  Diag  Time
0    A     1    12 <-duplicates for same A, 1 different value
1    A     1    13 <-duplicates for same A, 1 different value
2    A     2    14
3    B     2    18
4    B     1     1
5    C     3     9
6    C     2     8

df = df.pivot_table(index='Name',columns='Diag', values='Time', aggfunc='mean')
print (df)
Diag     1     2    3
Name                 
A     12.5  14.0  NaN
B      1.0  18.0  NaN
C      NaN   8.0  9.0

Alternative solution: 替代解决方案:

df = df.groupby(['Name','Diag'])['Time'].mean().unstack()
print (df)
Diag     1     2    3
Name                 
A     12.5  14.0  NaN
B      1.0  18.0  NaN
C      NaN   8.0  9.0

EDIT: 编辑:

You can also check all duplicates by duplicated : 您还可以按duplicated检查所有重复duplicated

df = df.loc[df.duplicated(['Name','Diag'], keep=False), ['Name','Diag']]
print (df)
  Name  Diag
0    A     1
1    A     1

EDIT: 编辑:

mean of datetimes is not easy - need convert dates to nanoseconds , get mean and last convert to datetimes. 日期时间的mean并不容易-需要将日期转换为nanoseconds ,获取平均值并最后转换为日期时间。 Also there is another problem - need replace NaN to some scalar, eg 0 what is converted to 0 datetime - 1970-01-01 . 另外还有一个问题-需要将NaN替换为某个标量,例如0转换为0 datetime- 1970-01-01

df.Date = pd.to_datetime(df.Date)
df['dates_in_ns'] = pd.Series(df.Date.values.astype(np.int64), index=df.index)
df = df.pivot_table(index='Name',
                    columns='Diag', 
                    values='dates_in_ns', 
                    aggfunc='mean', 
                    fill_value=0)
df = df.apply(pd.to_datetime)
print (df)
Diag                   1          2          3
Name                                          
A    2000-07-07 12:00:00 2001-07-23 1970-01-01
B    2016-10-12 00:00:00 1999-09-12 1970-01-01
C    1970-01-01 00:00:00 1998-08-20 2010-01-20

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM