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在JavaScript中创建父母子女的数组

[英]Create an array of a parents children in javascript

I am trying to create an array of a parent div's ( id="lol" ) children and them fetch them to change display:none; 我正在尝试创建父div( id="lol" )子级的数组,它们获取它们以更改display:none; except for the child with id="a" . 除了id="a"的孩子。 I've tried this but it doesn't work. 我已经尝试过了,但是没有用。 How can I improve this to get it to work? 我如何改进它才能使其正常工作?

function myFunction() {

  var x = document.getElementById('a');

  var children = [].slice.call(document.getElementById('lol').getElementsByTagName('*'),0);
  var arrayLength = children.length;          

  for (var i = 0; i < arrayLength; i++) {
    var name = children[i].getAttribute('id');
    var z = document.getElementById(name);
    z.style.display = 'none';
  }
  x.style.display = 'block';
} 

If every child has an id attribute than it will work. 如果每个孩子都有一个id属性,它将起作用。 Otherwise, some children might not have id attribute, in that case variable z will be undefined and accessing style property over z which is undefined will give error. 否则,有些孩子可能没有id属性,在这种情况下,变量zundefined和访问style对财产z这是undefined会给错误。 Simple fix would be just handling undefined variable: 简单的解决方法就是处理undefined变量:

   if(z)      
       z.style.display = 'none';

Same goes with variable x , too. 变量x也是如此。

How about using jQuery? 如何使用jQuery?

$('#lol').children(':not(#a)').hide();

If jQuery is not an option you can do this: 如果没有jQuery选项,则可以执行以下操作:

var lol = document.getElementById('lol');
var children = lol.querySelectorAll(':not(#a)');
for(var i=0;i<children.length;i++) {
    children[i].style.display = 'none';
}

Even more "low-level": 更“低级”:

var lol = document.getElementById('lol');
var children = lol.childNodes;
for(var i=0;i<children.length;i++){
    if(children[i].id != 'a') {
        children[i].style.display = 'none';
    }
}
function myFunction() {


  var children = [].slice.call(document.getElementById('lol').getElementsByTagName('*'),0);
  var arrayLength = children.length;          

  for (var i = 0; i < arrayLength; i++) {
   children[i].style.display = 'none';
  }
  document.getElementById('a').style.display = 'block';
} 

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