确认表单并显示消息（如果表单对JQuery有效）

Question

I'm developing my Django application and I would like to use JavaScript in order to improve my website.

I have a form and I would like to display 2 things :

• Confirm the form before submit
• If form is well submitted, display a message : 'Form is saved'

It's the first time I'm using JS and I need help to make this process.

This is my code :

    <form class = "form" method='POST' action=''> {% csrf_token %}
        <br></br>
        {{ form.as_p}}
        <br></br>

        <button type="submit">Valider</button>
    </form>

    <script>
        $('#form').submit(function() {
        var c = confirm("Click OK to continue?");
        return c; //you can just return c because it will be true or false
    });
    </script>

And if my form is valid and saved :

<script type="text/javascript" >
                $(document).on('Valider', 'form.form', function(form) {
                var $form = $(form);
                $.ajax({
                    url:"/path_to_my_html_file/BC_form2.html",
                    type: "POST",
                    success: function(form) {
                    alert("Form is saved");
                    }
                });
                });
            </script>

Could you help me ?

Thank you

Answer 1

You can try to adopt by your purpose this code:

 $('#form').submit(function(e) { // Prevents form to be submitted by default post request with page reloading e.preventDefault(); if (confirm("Click OK to continue?")) { // Here you can call your AJAX request callAjax($('input[type=text]').val()) } }); function callAjax(value) { // Making AJAX request to your endpoint // GET ipify just for example $.ajax({ url:"https://api.ipify.org?format=json", type: "GET", success: function(form) { alert("Form is saved"); } }); } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <form id="form"> <input type="hidden" value="MOCK FOR CSRF TOKEN" /> <br></br> <input type="text" required /> <br></br> <button type="submit">Valider</button> </form> 

Answer 2

Use .valid() in submit function

$('#form').submit(function() {
  var isValid=$("#form").valid();
           if (isValid) { //If there is no validation error

            var c = confirm("Click OK to continue?");
            if(c){
              $.ajax({
                url:"/path_to_my_html_file/BC_form2.html",
                type: "POST",
                success: function(form) {
                  alert("Form is saved");
                }
              });

            }

          } 
          else {
            alert('form is not valid');                               
          }

        });
</script>