SQL Server：如何从临时表中插入多行数据，并在临时表中存储插入的行的ID

Question

I am trying insert 1 row into an audit table for every row in a temporary table and store the ID of each audit table row in the temporary table.

The columns inserted into the audit table will come from the rows in the temporary table and I will need to refer back to the audit.id via the temporary table (so they need to match correctly)

I do not want to use any loops.

Answer 1

Without any example tables, data, and desired results, here is my attempt at a solution using output and a table variable.

create table t (id int not null identity(1,1), val varchar(32), audit_id int null);
insert into t (val) values ('three'),('two'),('one');
create table audit (id int not null identity(1,1), val varchar(32));

/* table variable for output */
declare @output table (id int, val varchar(32));

/* insert with output */
insert into audit (val)
output inserted.id, inserted.val into @output
select val
from t;

/* updated t from output */
update t 
set audit_id = o.id
from t
  inner join @output o
    on t.val = o.val;

select * from audit;
select * from t;

rextester demo: http://rextester.com/JMOT34416

for the audit table, returns:

+----+-------+
| id |  val  |
+----+-------+
|  1 | three |
|  2 | two   |
|  3 | one   |
+----+-------+

and for the temporary table t

+----+-------+----------+
| id |  val  | audit_id |
+----+-------+----------+
|  1 | three |        1 |
|  2 | two   |        2 |
|  3 | one   |        3 |
+----+-------+----------+