[英]C++14 increment a value inside of lambda function with capture-specifier
My task is to write a lambda function which increment a value, but I have to use value = 0 capture-specifier. 我的任务是编写一个增加值的lambda函数,但我必须使用value = 0 capture-specifier。 I'm thinking about the following function:
我正在考虑以下功能:
auto lambda = [value = 0]{return ++value}
When this function is called it has to give an incremented value every time. 调用此函数时,每次都必须给出递增的值。 But I know this implementation is wrong, because it's passed by value.
但我知道这个实现是错误的,因为它是通过值传递的。 How can I do this in C++14?
我怎么能用C ++ 14做到这一点?
你需要使lambda变为可变:
auto lambda = [value = 0]() mutable {return ++value;};
You don't need a capture: 你不需要捕获:
[]{ static int i=0; return ++i; }
Is all you need. 是你所需要的全部。
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