替换 typescript 中字符串中的所有字符实例？

Question

I'm trying to replace all full stops in an email with an x character - for example "my.email@email.com" would become "myxemail@emailxcom". Email is set to a string.
My problem is it's not replacing just full stops, it's replacing every character, so I just get a string of x's.
I can get it working with just one full stop, so I'm assuming I'm wrong on the global instance part. Here's my code:

let re = ".";
let new = email.replace(/re/gi, "x");

I've also tried

re = /./gi;
new = email.replace(re, "x");

If anyone can shed any light I'd really appreciate it, I've been stuck on this for so long and can't seem to figure out where I'm going wrong.

** Edit: Whoops, my new variable was actually called newemail, keyword new wasn't causing the issue!

Answer 1

Your second example is the closest. The first problem is your variable name, new , which happens to be one of JavaScript's reserved keywords (and is instead used to construct objects, like new RegExp or new Set ). This means that your program will throw a Syntax Error.

Also, since the dot ( . ) is a special character inside regex grammar, you should escape it as \\. . Otherwise you would end up with result == "xxxxxxxxxxxxxxxxxx" , which is undesirable.

 let email = "my.email@email.com" let re = /\\./gi; let result = email.replace(re, "x"); console.log(result) 

Answer 2

You may just use replaceAll() String function, described here: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/String/replaceAll

If you are getting Property 'replaceAll' does not exist on type 'string' error - go to tsconfig.json and within "lib" change or add "es2021".

Like this:

More info here: Property 'replaceAll' does not exist on type 'string'

Answer 3

You can try split() and join() method that was work for me. (For normal string text) It was short and simple to implement and understand. Below is an example.

let email = "my.email@email.com";
email.split('.').join('x');

So, it will replace all your . with x . So, after the above example, email variable become myxemail@gmailxcom