为什么不能在递归lambda函数中使用auto？

Question

This is code inside my mergeSort method,

    std::function<void(std::vector<T>*)> mergeSortRange = [&](std::vector<T>* array) -> void {
        int length = (int) array->size();
        if (length < 2)
            return;
        std::vector<T>* leftArr = new std::vector<T>(array->begin(), array->begin() + length / 2);
        std::vector<T>* rightArr = new std::vector<T>(array->begin() + length / 2, array->end());
        mergeSortRange(leftArr);
        mergeSortRange(rightArr);
        mergeTwoSortedArrrays(leftArr, rightArr, array);
        delete leftArr;
        delete rightArr;
    };

I could have substituted the first line with:

auto mergeSortRange = [&](std::vector<T>* array) -> void , and I'd expect it to work fine (excuse my ignorance).

But instead the compiler complains saying:

Variable 'mergeSortRange' declared with 'auto' cannot appear in its own initializer.

I have specified both the parameters and the return type. Could somebody throw some light on this?

Answer 1

Your program is ill-formed because as Riad says, you are trying to call the function before the type is deduced:

dcl.spec.auto/10 If the type of an entity with an undeduced placeholder type is needed to determine the type of an expression, the program is ill-formed. Once a non-discarded return statement has been seen in a function, however, the return type deduced from that statement can be used in the rest of the function, including in other return statements.