如何逐行读取2个不同的文本文件，并使用python制作另一个包含字典的文件？

Question

I have two text files name weburl.txt and imageurl.txt , weburl.txt contain URLs of website and imageurl.txt contain all images URLs I want to create a dictionary that read a line of weburl.txt and make key of a dictionary and imageurl.txt line as a value. weburl.txt

url1
url2
url3
url4
url5......

imageurl.txt

imgurl1
imgurl2
imgurl3
imgurl4
imgurl5

required output is

 {'url1': imgurl1, 'url2': imgurl2, 'url3': imgurl3......}

I am using this code

with open('weburl.txt') as f :
  key = f.readlines()
  with open('imageurl.txt') as g:  
    value = g.readlines()
    dict[key] = [value]

  print dict

I am not getting the required results

Answer 1

you can write something like

with open('weburl.txt') as f, \
        open('imageurl.txt') as g:
    # we use `str.strip` method
    # to remove newline characters
    keys = (line.strip() for line in f)
    values = (line.strip() for line in g)
    result = dict(zip(keys, values))

print(result)

more info about zip at docs

Answer 2

There are problems with the statement dict[key] = [value] on so many levels that I get a kind of vertigo as we drill down through them:

1. The apparent intention to use a variable called dict (a bad idea because it would overshadow Python's builtin reference to the dict class). Let's call it d instead.
2. Not initializing the dictionary instance first. If you had called it something like d this oversight would earn you an easy-to-understand NameError . However since you're calling it dict , Python will actually be attempting to set items in the dict class itself (which doesn't support __setitem__ ) instead of inside a dict instance, so you'll get a different, more-confusing error.
3. Attempting to make a dict entry assignment where the key is a non-hashable type ( key is a list ). You could convert the list to the hashable type tuple easily enough, but that's not what you want because you'd still be...
4. Attempting to assign bunch of values to their respective keys all at once . This can't be done with d[key] = value syntax. It could be done all in one relatively simple statement, ie d=dict(zip(key,value)) but unfortunately that doesn't get around the fact that you're...
5. Not stripping the newline character off the end of each key and value.

Instead, this line:

d = dict((k.strip(), v.strip()) for k, v in zip(key, value))

will do what you appear to want.