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不同的和最新的意见书

[英]Distinct and latest submissions

I have a table where each customer can submit many requests, but only latest requests would be entertained. 我有一张桌子,每个客户都可以提交许多请求,但只有最新的请求可以受理。

For example, Customer1 may have only submitted 1 request and CustomerX may have submitted 10 requests. 例如,Customer1可能仅提交了1个请求,而CustomerX可能已提交了10个请求。 So when I pull the report it would bring the 1 request by customer1 and the 10th request by CustomerX. 因此,当我提取报表时,它将带来customer1的1请求和CustomerX的第十个请求。

How can I do that? 我怎样才能做到这一点?

Customer Id, FoodSelection1, FoodSelection2, DateSubmitted 客户ID,FoodSelection1,FoodSelection2,提交日期

You can use the WITH TIES clause in concert with Row_Number() 您可以将WITH TIES子句与Row_Number()配合使用

Select Top 1 with ties *
 From YourTable
 Order By Row_Number() over (Partition By CustomerID Order by DateSubmitted Desc)
SELECT m.CustomerId, m.FoodSelection1, m.FoodSelection2, m.DateSubmitted FROM tblpm m 
  WHERE m.DateSubmitted =(SELECT max(n.DateSubmitted ) FROM tblpm n 
                       where n.CustomerId=m.CustomerIdORDER)
select * from MyTable T1 
where not exists --exclude records where 
(
select 1 from MyTable T2 
where T1.[Customer Id]=T2.[Customer Id] --there is matching rcd for customer
and T1.DateSubmitted<T2.DateSubmitted --a newer one exists
)
select 
    t.Customer, 
    t.id, 
    t.FoodSelection1, 
    t.FoodSelection2, 
    t.DateSubmitted 
from MyTable T1 as t 
where t.datesubmited in 
     (select max(r.datesubmited) 
      from table 1 as r
      where t.idCustomer = r.idCustomer
      group by r.idcustomer)

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