[英]Array of pointers to circle struct
I have a array of 50 pointers that point to a circle struct that contains the x and y center coordinates, and the radius for a circle. 我有一个由50个指针组成的数组,这些数组指向一个圆形结构,该结构包含x和y中心坐标以及一个圆的半径。 I allocated all of the memory and used
rand_float
to create random x, y, and z for the circles. 我分配了所有内存,并使用
rand_float
为rand_float
创建了随机的x,y和z。 The point to my program is the find the circle with the largest area and print it out. 我程序的重点是找到面积最大的圆并将其打印出来。 I am experiencing problems with my program, I understand that with rand results will not be the same every time but my values are no where near the intended output.
我的程序遇到问题,我知道每次使用rand的结果都不会相同,但是我的值与预期输出不符。 I am also not seeing the
printf
output from largestcircle
in the output. 我也没有在输出中看到
largestcircle
的printf
输出。 Lastly I receive a error when I try running the program with free(circleptr
). 最后,当我尝试使用
free(circleptr
)运行程序时收到错误free(circleptr
。
#include <stdio.h>
#include <stdlib.h>
#define PI 3.14
double rand_float(double a,double b){ //function provided my teacher.
return ((double)rand()/RAND_MAX)*(b-a)+a;
}
struct circle{
double x;
double y;
double z;
};
void largestcircle(struct circle **circleptr){
float max = 0, radius =0, x= 0, y=0;
int i;
for(i = 0; i<50; i++){
if(circleptr[i]->z *circleptr[i] ->z *PI > max){
max = circleptr[i]->z*2*PI;
radius = circleptr[i]->z;
x = circleptr[i] ->x;
y = circleptr[i] ->y;
}
}
printf("Circle with largest area (%f) has center (%f, %f) and radius %f\n", max,x,y,radius);
}
int main(void) {
struct circle *circleptr[50];
//dynamically allocate memory to store a circle
int i;
for(i=0; i<50; i++){
circleptr[i] = (struct circle*)malloc(sizeof(struct circle));
}
//randomly generate circles
for(i=0; i<50; i++){//x
circleptr[i]->x = rand_float(100, 900);
circleptr[i]->y = rand_float(100, 900);
circleptr[i]->z = rand_float(0, 100);
//printf("%11f %11f %11f \n", circleptr[i] ->x, circleptr[i]->y, circleptr[i]->z);
}
largestcircle(circleptr);
for(i=0; i<50; i++){
free(circleptr[i]);
}
return 0;
}
the output should look something like: 输出应类似于:
Circle with largest area (31380.837301) has center (774.922941,897.436445) and radius 99.969481
My current xy and z values look like: 我当前的xy和z值如下所示:
1885193628 -622124880 -622124884
1885193628 -622124868 -622124872
1885193628 -622124856 -622124860
1885193628 -622124844 -622124848
1885193628 -622124832 -622124836
1885193628 -622124820 -622124824
1885193628 -622124808 -622124812
1885193628 -622124796 -622124800
1885193628 -622124784 -622124788
1885193628 -622124772 -622124776......etc.
Thoughts? 有什么想法吗?
The problem where you are seeing some garbage random values for circle->x, y and z is is with your format specifier, while you are printing the circle->x
, circle->y
and circle->z
. 当您打印
circle->x
, circle->y
和circle->z
,格式说明符是您看到circle-> x,y和z的一些垃圾随机值的问题。 Use %f
instead of %d
since you are using double
and not an int
. 使用
%f
而不是%d
因为您使用的是double
而不是int
。
printf("%d %d %d \n", circleptr[i]->x, circleptr[i]->y, circleptr[i]->z);
Change above to 更改为
printf("%f %f %f \n", circleptr[i]->x, circleptr[i]->y, circleptr[i]->z);
Here is your problem, you re using %d
, use %llf
这是您的问题,您正在使用
%d
,请使用%llf
printf("%llf %llf %llf \n", circleptr[i] ->x, circleptr[i]->y, circleptr[i]->z);
printf("Circle with largest area (%llf) has center (%llf, %llf) and radius %llf\n", max, x, y, radius);
also you have a bit missclick here I
instead of i
while free memory 你也有一些missclick在这里
I
而不是I
而i
空闲内存
There is a problem with this function: 此功能有问题:
void largestcircle(struct circle **circleptr){
float max = 0, radius =0, x= 0, y=0;
int i;
for(i = 0; i<50; i++){
if(circleptr[i]->z *circleptr[i] ->z *PI > max){
max = circleptr[i]->z*2*PI;
radius = circleptr[i]->z;
x = circleptr[i] ->x;
y = circleptr[i] ->y;
}
}
printf("Circle with largest area (%f) has center (%f, %f) and radius %f\n", max,x,y,radius);
}
The if() statement compared for the area of a circle which is pie * r * r. if()语句比较了一个圆形区域,即pie * r * r。 But within if(), max is set to circumference of a circle which is 2 * pie * r.
但是在if()中,max设置为2 * pie * r的圆的周长。
This will give you the wrong answer. 这将给您错误的答案。
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