C编程sprinf问题

Question

I'm using sprintf to print int variable which should display 1^2+2^2+3^2+4^2+5^2+6^2 . But my code only prints 1^2+6^2 . I don't know why the middle part is missing.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char* formatSeries(int n)
{
  char *tagstr = (char *)malloc(sizeof(char)*n*n);

  int pos = 0 ;
  int k;

  for (k = 1; k <= n; k++)
  {
    pos = sprintf(&tagstr[pos], "%d^2+", k);
  }
  tagstr[strlen(tagstr) - 1] = '\0';

  return tagstr;
}

 void main()
{
  int n = 6;
  printf("%s \n", formatSeries(n));
}

Answer 1

There are two main issues in your code; the one - as already mentioned in the comments - is that you do not increase pos but reassign it again and again with (almost) the same value. Hence, after the first iteration, you will constantly write to a position at 4 (or 5 if k would become >=10 and the numbers would thereby get more digits),

Second, your malloc will not work for small k s, since each string like "+1^2" takes at least 4 characters; so if you size the buffer with n * n , then the buffer will be too small if n is <= 3, and (probably much) too big if n becomes larger.

I'd suggest to assume a maximum range of n (let's say up to 7 digits) and dimension the buffer accordingly.

A minor thing (and not essential) is that you probably could avoid writing superfluous + at all in that you use a different format string for the first iteration; just do show the idea, really not essential:

char* formatSeries(int n)
{
    const size_t maxSize = n * (7+3) + 1;

    char *tagstr = (char *)malloc(sizeof(char)*maxSize);

    int pos = 0 ;
    int k;
    for (k = 1; k <= n; k++)
    {
        const char* formatStr = (k==1) ? "%d^2" : "+%d^2";
        pos += sprintf(&tagstr[pos], formatStr, k);

    }
    return tagstr;
}