OSX：将文件复制到具有相同名称的文件夹

Question

I'm looking for a script of some sort, to copy about 800 files with separate case numbers ex: "1234567 - XXXX XXX" of which is placed in one folder, into a directory of another folder(a server) with the same case name, under a subfolder ex:

"1234567 - XXXX XXX/01_Management/01_Correspondence" (subfolder identical for all folders)

Sum up: Copying one file, to another folder with the same name as the file, placing it in a subfolder.

macOS Sierra

Thank you -Theis

Answer 1

You could do that with a bash script.

Make a back-up first!

Save the following in your HOME directory as reorganise :

#!/bin/bash

find $(pwd) -name "* -*" -print0 | while read -d $'\0' f; do
   echo Processing file $f...
   base=$(basename "$f")
   echo "   base: $base"
   case=${base/ -*/}
   echo "   case: $case"
   # EDIT THE FOLLOWING LINE TO BE CORRECT FOR YOU !!!
   newplace="/path/to/new/place/$case"
   echo mkdir -p "$newplace"
   echo cp "$f" "$newplace"
done

Then start Terminal and type the following just once to make the script executable:

chmod +x reorganise

Then go to the directory where your files are:

cd where/your/files/are

And then you can run the script with:

$HOME/organise

and it will tell you what it would do, without doing anything. If you like it, you can remove the word echo on the second and third to last lines and run it again.

You will need to edit the indicated line at least.

Sample Output

Processing file /Users/mark/tmp/1234563 - fredb...
   base: 1234563 - fredb
   case: 1234563
mkdir -p /path/to/new/place/1234563
cp /Users/mark/tmp/1234563 - fredb /path/to/new/place/1234563
Processing file /Users/mark/tmp/1234567 - fred...
   base: 1234567 - fred
   case: 1234567
mkdir -p /path/to/new/place/1234567
cp /Users/mark/tmp/1234567 - fred /path/to/new/place/1234567